Elastic head-on collision physics

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In an elastic head-on collision involving two equal mass billiard balls, one ball traveling at 4.0 m/s collides with a stationary ball. After the collision, the first ball comes to a complete stop while the second ball moves forward at the same speed of 4.0 m/s. The momentum conservation principle confirms that the second ball takes on the velocity of the first ball. The discussion clarifies that the initial ball's momentum is transferred entirely to the second ball. This scenario illustrates the fundamental principles of elastic collisions in physics.
Eminem04
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I need help with this problem. I tried it myself but I'm not sure if it's correct ( i got 4 m/s )
A billiard ball traveling at 4.0 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?
 
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How did you get your answer?
 
I got my answer by using M*Vi=M*Vf
 
Last edited:
First you what to find the momentum of both cars then divide that answer by the combined mass of the two cars. But in your case since you have one car moving and one is stationary the answer is half of your moving cars velocity.
 
Kacper's response about "cars" confuses me!


Eminem04: Yes, your answer is completely correct. Since the two balls have the same mass and one stopped completely, the other continues forward with the same speed as the initial ball. (In a sense, it just "replaces" the first ball.)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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