Elastic head-on collision physics

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Homework Help Overview

The problem involves an elastic head-on collision between two billiard balls of equal mass, where one ball is initially moving and the other is at rest. The original poster is uncertain about their calculated speed of the second ball after the collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss momentum conservation and the implications of equal mass in elastic collisions. Questions arise regarding the methods used to derive the speed of the second ball, with some participants referencing momentum equations.

Discussion Status

There is a mix of interpretations regarding the calculations and reasoning behind the answers. Some participants express confusion over certain explanations, while others affirm the correctness of the original poster's answer, suggesting a productive exchange of ideas.

Contextual Notes

Participants note the specific conditions of the problem, including the equal mass of the billiard balls and the initial state of one ball being at rest. There is mention of differing terminology, such as references to "cars," which may introduce ambiguity in the discussion.

Eminem04
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I need help with this problem. I tried it myself but I'm not sure if it's correct ( i got 4 m/s )
A billiard ball traveling at 4.0 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?
 
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How did you get your answer?
 
I got my answer by using M*Vi=M*Vf
 
Last edited:
First you what to find the momentum of both cars then divide that answer by the combined mass of the two cars. But in your case since you have one car moving and one is stationary the answer is half of your moving cars velocity.
 
Kacper's response about "cars" confuses me!


Eminem04: Yes, your answer is completely correct. Since the two balls have the same mass and one stopped completely, the other continues forward with the same speed as the initial ball. (In a sense, it just "replaces" the first ball.)
 

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