Electric Dipole: Calculate Electric Field at a Distance

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SUMMARY

The discussion focuses on calculating the electric field at a distant point along the x-axis for an electric dipole, defined by two point charges. The derived formula for the electric field is E_{x}=\frac{4k_{e}qa}{x^3}, where k_{e} is Coulomb's constant, q is the charge magnitude, a is the distance between the charges, and x is the distance from the dipole. Participants clarify the vector nature of electric fields and the importance of correctly applying the electric field equation E=\frac{k_{e}q}{r^2} to account for the positions of the charges.

PREREQUISITES
  • Understanding of electric dipoles and their properties
  • Familiarity with Coulomb's law and electric field equations
  • Knowledge of vector addition in physics
  • Basic calculus for understanding limits and approximations
NEXT STEPS
  • Study the derivation of the electric field for dipoles in detail
  • Learn about the implications of distance in electric field calculations
  • Explore the concept of electric field lines and their representation
  • Investigate the effects of varying charge magnitudes on electric field strength
USEFUL FOR

Students in physics, particularly those studying electromagnetism, educators teaching electric field concepts, and anyone interested in advanced applications of electric dipoles in theoretical physics.

vipertongn
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Homework Statement
Two point charges likes those in the figure below are called an electric dipole. Show that the electric field at a distant point along the x-axis is given by [tex]E_{x}=\frac{4k_{e}qa}{x^3}[/tex]
Figure: http://img300.imageshack.us/my.php?image=58ag9.png

Homework Equations


Electric field equation: [tex]E=\frac{k_{e}q}{r^2}[/tex]


The Attempt at a Solution



I know that the total electric field at some point equals the vector sum of the electric fields of both charges. So...

-kq/r^2+kq/r^2?

From the solutions it puts in x-a and x+a for r values (x+a was orignally x-(-a)). I want to know why its subtracting the vector.
 
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vipertongn said:
Homework Statement
Two point charges likes those in the figure below are called an electric dipole. Show that the electric field at a distant point along the x-axis is given by [tex]E_{x}=\frac{4k_{e}qa}{x^3}[/tex]
Figure: http://img300.imageshack.us/my.php?image=58ag9.png

Homework Equations


Electric field equation: [tex]E=\frac{k_{e}q}{r^2}[/tex]


The Attempt at a Solution



I know that the total electric field at some point equals the vector sum of the electric fields of both charges. So...

-kq/r^2+kq/r^2?

From the solutions it puts in x-a and x+a for r values (x+a was orignally x-(-a)). I want to know why its subtracting the vector.

Did you check the signs on the q's?
 

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