Electric displacement of a uniformly polarized sphere

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tanzhongm
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Homework Statement



Suppose we have a uniformly polarized sphere of radius R. The polarization vector is [tex]\mathbf{P}[/tex].

Goal: To find the electric field everywhere.

Homework Equations


I know the actual solution already. It should be [tex]\mathbf{E} = \frac{-1}{3 \epsilon_0} \mathbf{P}[/tex]

The Attempt at a Solution


However, if we use Gauss' Law [tex]\oint \mathbf{D} \cdot d\mathbf{A} = Q_{enc,free}[/tex].

We get [tex]Q_{enc,free}=0[/tex]

Hence, [tex]\mathbf{D}=0[/tex] and [tex]\epsilon_0 \mathbf{E}=\mathbf{P}[/tex]

Therefore, [tex]\mathbf{E} = \frac{\mathbf{P}}{\epsilon_0}[/tex].

But these two values are different.
 
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You can't use Gauss' law for the D-field if you don't have a symmetrical problem.In other words, since the polarisation is not spherically symmetric Gauss' law for the D-field with the free charge on the right hand side is not valid. Remember that curl of D is not zero, but equal to minus the curl of P if i remember correctly.

To find the E-field everywhere you can set up a boundary value problem for the electric potential with appropriate boundary conditions at the boundary of the sphere.