Electric field between parallel plates

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 2K views
lys04
Messages
144
Reaction score
5
Homework Statement
The electric field outside a conducting plate of charge is given by sigma/epsilon right? Then why not for a capacitor, since that is 2 conducting plates, is the electric field 2sigma/epsilon using superposition principle?
Relevant Equations
E=sigma/epsilon
^^
 
Physics news on Phys.org
Here’s a cross -section through (due to space limitations, part of) an infinite conducting plate with a (say) positive charge:
___________________________
___________________________

Here are some questions to consider:
- are both surfaces charged?
- if only one (of the two) surfaces is charged, what determines which one?
- in a static situation, every ‘field line’ starts on a positive charge and ends on a negative charge; where are the negative charges here?
 
Reply
  • Like
Likes   Reactions: MatinSAR
lys04 said:
Homework Statement: The electric field outside a conducting plate of charge is given by sigma/epsilon right? Then why not for a capacitor, since that is 2 conducting plates, is the electric field 2sigma/epsilon using superposition principle?
Relevant Equations: E=sigma/epsilon
Generally, the two plates of a capacitor are oppositely charged. Right?

So, if one plate has a surface charge density, ##\sigma##, then the other plate has surface charge density, ##-
\sigma##,

Now use superposition to determine the electric field outside the plates as well as between the plates.
 
Reply
  • Like
Likes   Reactions: MatinSAR