Electric field inside a hollow conductive sphere

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SUMMARY

The electric field inside a hollow conductive sphere is zero, regardless of the charge placed on it, as established by electrostatic principles. Even with a minimal charge, such as two electrons, the vast number of conduction electrons in the sphere will redistribute to maintain this zero field. This phenomenon is due to the ability of free electrons in conductors, like copper, to move and realign in response to external charges. The discussion also clarifies that free electrons do not imply an excess of electrons over protons in metals, as the number of free electrons corresponds to those available for conduction, not the total atomic count.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with conductive materials and their properties
  • Basic knowledge of atomic structure, particularly in metals like copper
  • Concepts of conduction electrons and valence electrons
NEXT STEPS
  • Research "Electrostatics and Gauss's Law" for deeper insights into electric fields in conductors
  • Study "Conductivity in Metals" to understand the behavior of free electrons
  • Explore "Valence and Conduction Electrons in Metals" for clarity on electron distribution
  • Investigate "Solid State Physics" to learn about the lattice structure of metals and electron flow
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Students and professionals in physics, electrical engineering, and materials science who seek to understand the behavior of electric fields in conductive materials and the properties of electrons in metals.

TonyZ
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Hello,
This is my first post to these forums.

It is well known that the electric field inside a conducting
sphere is zero everywhere inside. But what if the charge
placed on the sphere is very, very small. Let's say it
consists of only two electrons. Clearly, this small charge cannot
be evenly distributed on the surface of the sphere. The
two electrons will undoubtedly end up as far apart as possible,
i.e. at opposite sides of the sphere. It doesn't appear that
the electric field is zero everywhere inside this sphere.

I'd like to get the group's input on this.

Thanks!
Tony
 
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A conducting sphere will have many free electrons, and it will be no problem for them to spread evenly.
A charged sphere of copper might consist of 10^24 copper ions and 10^24+2 electrons in the conduction band that can all move around.
 
The theorems about conductors generally assume a huge number of conduction electrons as willem2 says. If only two electrons are added to a conductor, the lare number of conduction electrons will realign to produce zero field inside. That is, adding two newborns to the world population does not change much, except for their families.
 
Thanks to all who replied! I understand what you are saying.

I have one other question: Are the "free electrons" in a metalic conductor those which are above and beyond the ones that are part of the metal atoms? For example, copper atoms have 29 electrons and 29 protons. Does having free electrons mean there are more electrons than protons? If so, wouldn't that mean that every metal is inherently
negatively charged (which I know is not correct)?

Thanks,
Tony


Tony
 
TonyZ said:
I have one other question: Are the "free electrons" in a metalic conductor those which are above and beyond the ones that are part of the metal atoms? For example, copper atoms have 29 electrons and 29 protons. Does having free electrons mean there are more electrons than protons?

There are as many electrons as there are protons. A fraction of the 29 are conducting and the rest are not (valence electrons). I don't know how many of the 29 are valence and how many are conducting, but it should be a well-known constant number at room temperature for copper specialists (probably in a table somewhere, and quite readily calculable with the basic theory).

In condensed matter/solid state theory, a crystal (including a metallic polycrystal) is considered a lattice of (+) ions, through which conducting electrons flow, not a lattice of (neutral) atoms.
 

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