Electric field inside a sphere of charge

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SUMMARY

The electric field inside a uniformly charged sphere can be determined using Gauss's Law. When applying this law, a Gaussian surface is drawn inside the sphere, which encloses no charge. Consequently, the total electric flux through this surface is zero, indicating that the electric field within the sphere is also zero. This occurs because the vector sum of the electric fields from the external charges cancels out, resulting in no net contribution to the field inside the sphere.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and flux concepts
  • Knowledge of vector addition in physics
  • Basic principles of electrostatics
NEXT STEPS
  • Study the application of Gauss's Law in different charge distributions
  • Explore the concept of electric field lines and their behavior around charged objects
  • Learn about the implications of superposition in electric fields
  • Investigate the relationship between electric field strength and distance from a charged sphere
USEFUL FOR

Students of physics, educators teaching electrostatics, and anyone seeking to deepen their understanding of electric fields and Gauss's Law.

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So I understand that to find the electric field inside a sphere of charge you can use Gauss's Law by drawing a sphere inside, enclosing the charge. But, intuitively, I don't understand it.. why don't the charges outside this sphere contribute to the electric field? I know the total flux through the sphere you've drawn will be zero, but I don't know, it just doesn't make sense visually to me.
 
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The fields due to the charges outside the sphere all point in different directions. The vector sum of these fields, as it turns out, adds up to zero.
 

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