Electric field inside a uniformly charged solid sphere .

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In a uniformly charged solid sphere, charges distribute on the surface only if the sphere is a conductor. For a non-conducting sphere, the electric field inside increases linearly with distance from the center. This behavior contrasts with that of a hollow sphere or charged ring, where the electric field inside is zero. The distinction arises from the nature of charge distribution in conductors versus non-conductors. Understanding these principles clarifies the electric field behavior in different charged objects.
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Homework Statement


It is just a conceptual question.
I learned that all charges tend to move toward outer surface, meaning all the charges of the solid sphere will be on the surface of the solid sphere.
Then, why is it that the electric field increases linearly with distance? shouldn't it be just 0? the same as hollow sphere or a charged ring.



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all the charges of the solid sphere will be on the surface of the solid sphere
provided the sphere is a conductor. For uniformly charged non-conducting sphere, the electric field in side the sphere increases linearly with distance from the center.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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