Electric Field inside an insulating sphere

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Homework Help Overview

The problem involves determining the electric field inside an insulating sphere with a uniform charge distribution. The original poster is trying to understand how to apply the relevant equations to find the electric field at a distance r from the center of the sphere.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the formula E=kQ/r^2, questioning how it relates to the charge distribution within the sphere. There is an exploration of how to calculate the enclosed charge at a distance r and the implications of uniform charge distribution.

Discussion Status

Some participants are actively engaging with the problem, questioning assumptions about the charge enclosed and the application of formulas. There is a recognition of the need to consider the volume of the sphere in relation to the total charge, and some guidance has been offered regarding the interpretation of the variables involved.

Contextual Notes

Participants are navigating the complexities of applying known formulas to a non-point charge scenario, with an emphasis on understanding the relationship between the total charge and the charge enclosed within a smaller radius. There is an acknowledgment of potential confusion stemming from memorized equations without full comprehension.

zgs
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I think this should an easy one:

Homework Statement

Consider an insulating sphere of radius R centered on the origin with total charge Q uniformly distributed throughout the volume of the sphere. What is the electric field E inside the sphere at a distance r from the origin? (i.e. r<R)


Homework Equations


They list Vshpere=4/3 ∏r^3 and Asphere=4∏r^2
I know E=kQ/r^2=f/q

The Attempt at a Solution


Multiple choice and I thought it was just E=kQ/r^2. Answer is really E=kQr/R3. Where did R^3 come from? I have to be missing an equation from my notes.. I must have to somehow incorporate the volume.
 

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This requires a little thinking. The Q in the kQ/r^2 formula represents the charge of a point charge. That isn't the Q you're given. This is a fairly standard trick to fool students who memorize formulas without understanding the full meaning of the variables. To be fair, real physicists make the same mistakes sometimes, too.

Tell me: how much charge is enclosed by the chunk of sphere out to a radius r?
 
Tricksters. It would still be Q because it is uniform. Right?

Edit: *All of it?
 
Last edited:
I got it! Ignore the above reply. Vr / VR = r^3/R^3. Multiply that by original equation, and that gets the right answer. So to sum it up for my sake of remembering on the exam; the Q is the whole sphere (a point at a distance) and to get the enclosed chunk I find the ratio of it to Q. -not the most clear summation of thought but I get what I'm trying to say I think. Thank you for getting my brain turning.
 

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