Electric field of a cylindrical capacitor

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SUMMARY

The discussion focuses on calculating the electric field of a cylindrical capacitor, consisting of a smaller cylindrical conductor with radius a and a larger cylindrical conductor with radius b, where b>a. The smaller cylinder carries a charge of +Q and the larger cylinder carries a charge of -Q. The electric field E is derived using Gauss's Law, resulting in the formula E = Q / (2 π r L ε0) for a Gaussian surface defined between the two cylinders. The discussion emphasizes the assumption that the length L of the cylinder is much greater than b to ensure the validity of the calculations.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with cylindrical coordinates
  • Knowledge of electric field concepts
  • Basic principles of capacitor design
NEXT STEPS
  • Study the implications of the assumption L >> b in cylindrical capacitor calculations
  • Explore the derivation of electric fields in parallel plate capacitors
  • Learn about the behavior of electric fields in different geometries
  • Investigate the effects of varying charge distributions on electric fields
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Students and professionals in physics, electrical engineering, and anyone studying electrostatics or capacitor design will benefit from this discussion.

Eigenvaluable
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Homework Statement


Calculate the electric field of a cylindrical capacitor comprised of a smaller cylindrical conductor of radius ##a## enclosed within a larger cylindrical conductor of radius ##b## where ##b>a##. The smaller cylinder has charge ##+Q## and the larger cylinder has charge ##-Q##.

Homework Equations


$$\oint \vec{\mathbf{E}} \cdot \vec{\mathbf{dA}} = \frac{Q_{\text{enclosed}}}{\epsilon_0}$$

The Attempt at a Solution


I've already solved the problem, as follows:

Define a Gaussian surface in which the cylinder completely encloses the smaller cylinder and is completely within the larger cylinder, i.e. a Gaussian cylinder with radius ##r## where ##a<r<b##.

Furthermore, let ##L## denote the length of the cylinder.

$$(2 \pi r L) E = \frac{Q_{\text{enclosed}}}{\epsilon_0}$$
$$E = \frac{Q}{2 \pi r L \epsilon_0}$$

While this is trivially easy, this reference sheet assumes that ##L >> b## prior to calculating anything.

Why must this be done?

Thank you,
Eigenvaluable
 
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Hello Eigenvaluable, Welcome to PF.

Eigenvaluable said:

Homework Statement


Calculate the electric field of a cylindrical capacitor comprised of a smaller cylindrical conductor of radius ##a## enclosed within a larger cylindrical conductor of radius ##b## where ##b>a##. The smaller cylinder has charge ##+Q## and the larger cylinder has charge ##-Q##.

Homework Equations


$$\oint \vec{\mathbf{E}} \cdot \vec{\mathbf{dA}} = \frac{Q_{\text{enclosed}}}{\epsilon_0}$$

The Attempt at a Solution


I've already solved the problem, as follows:

Define a Gaussian surface in which the cylinder completely encloses the smaller cylinder and is completely within the larger cylinder, i.e. a Gaussian cylinder with radius ##r## where ##a<r<b##.

Furthermore, let ##L## denote the length of the cylinder.

$$(2 \pi r L) E = \frac{Q_{\text{enclosed}}}{\epsilon_0}$$
$$E = \frac{Q}{2 \pi r L \epsilon_0}$$

While this is trivially easy, this reference sheet assumes that ##L >> b## prior to calculating anything.

Why must this be done?
A similar stipulation is made in the analysis of parallel plate capacitors where the plate dimensions are taken to be much larger than the plate separation. Consider the assumptions being made about the field between the capacitor plates. Do they hold true everywhere?
 

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