Electric Field of a Spherical Insulator

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
5 replies · 2K views
Stealth849
Messages
38
Reaction score
0

Homework Statement



A spherical insulator of radius R and charge density ρ = ρo/r2 where r is the distance from its centre. Find the electric field at a point inside and outside the insulator.


Homework Equations



EA = Qencl/εo

The Attempt at a Solution



What's throwing me off is the charge density. Setting up a gaussian sphere, I don't know what to do to find Q for the formula.
 
Physics news on Phys.org
You need to integrate he charge density enclosed in the Gaussian surface.

ehild
 
Can you elaborate a little bit?

I'm not too sure what I should be integrating here...

ρ should be in C/m3

To get Q from ρ, I need to cancel the volume... I don't see what to integrate to achieve this though.

Thanks
 
Charge density is the charge of unit volume. If it is constant you get the charge by simply multiplying the volume with the density.
The density varies with the distance from the centre here. But it is constant in a very thin shell.
What is the volume of a shell if its radius is r and thickness Δr?

ehild
 
hm,

if i integrate surface area from 0 ro the Radius, that would give me volume..

so if I take the integral of ρ*dA from 0 to R

where dA = 4*pi*r^2*dr ?
 
Yes, that will be the whole charge of the sphere. Calculate the field from it outside the charged sphere.
If the Gaussian surface is inside the charged sphere at distance r' < R from the centre, you need to integrate from 0 to r'.

ehild