Electric Field of a Spherical Insulator

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Homework Help Overview

The problem involves finding the electric field of a spherical insulator with a charge density that varies with distance from its center. The charge density is given as ρ = ρo/r², and the task is to determine the electric field both inside and outside the insulator.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to integrate the charge density to find the enclosed charge for use in Gauss's law. There are questions about how to set up the integration correctly, particularly regarding the variable charge density and the volume of the spherical shell.

Discussion Status

Some participants have provided guidance on integrating the charge density and calculating the volume of a shell. There is ongoing exploration of how to apply these concepts to find the total charge and subsequently the electric field.

Contextual Notes

Participants are navigating the complexities of a non-constant charge density and how it affects the integration process. There is a focus on understanding the relationship between charge density, volume, and the application of Gauss's law.

Stealth849
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Homework Statement



A spherical insulator of radius R and charge density ρ = ρo/r2 where r is the distance from its centre. Find the electric field at a point inside and outside the insulator.


Homework Equations



EA = Qenclo

The Attempt at a Solution



What's throwing me off is the charge density. Setting up a gaussian sphere, I don't know what to do to find Q for the formula.
 
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You need to integrate he charge density enclosed in the Gaussian surface.

ehild
 
Can you elaborate a little bit?

I'm not too sure what I should be integrating here...

ρ should be in C/m3

To get Q from ρ, I need to cancel the volume... I don't see what to integrate to achieve this though.

Thanks
 
Charge density is the charge of unit volume. If it is constant you get the charge by simply multiplying the volume with the density.
The density varies with the distance from the centre here. But it is constant in a very thin shell.
What is the volume of a shell if its radius is r and thickness Δr?

ehild
 
hm,

if i integrate surface area from 0 ro the Radius, that would give me volume..

so if I take the integral of ρ*dA from 0 to R

where dA = 4*pi*r^2*dr ?
 
Yes, that will be the whole charge of the sphere. Calculate the field from it outside the charged sphere.
If the Gaussian surface is inside the charged sphere at distance r' < R from the centre, you need to integrate from 0 to r'.

ehild
 

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