Electric field of point charges

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SUMMARY

The discussion centers on calculating the electric field generated by two identical positive point charges, each with a magnitude of 3.50 C, positioned at coordinates (0.190, 0) and (-0.190, 0). The correct formula for electric field strength is clarified as E = kq/r², where k is the electrostatic constant. Participants seek assistance in determining the electric field components and magnitude at the point (0.380, 0).

PREREQUISITES
  • Understanding of electric fields and point charges
  • Familiarity with the formula E = kq/r²
  • Basic knowledge of coordinate systems in physics
  • Concept of vector components in physics
NEXT STEPS
  • Study the concept of superposition of electric fields
  • Learn how to calculate electric field vectors from multiple point charges
  • Explore the implications of the electrostatic constant k in different mediums
  • Investigate the graphical representation of electric fields in coordinate systems
USEFUL FOR

Students in physics, educators teaching electrostatics, and anyone interested in understanding electric fields generated by point charges.

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hey guys i can't figure out this problem to save my life i thought i was doing it right using the
K=q/r^2 formula but its not coming out right. so if anyone can help me with this problem i would very much appreciate it.

In a rectangular coordinate system, a positive point charge = 3.50 is placed at the point x=0.190 ,y=0 , and an identical point charge is placed at x= -0.190 ,y=0 . Find the and components and the magnitude and direction of the electric field at the following points.

A) Find the and components and the magnitude and direction of the electric field at x=0.380, y=0.


B) Find E
 
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Find the what and the components?

E=kq/r^2, not k=q/r^2. k is a constant.
 

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