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Electric field problem — Changing the charge on two spheres

  • #1

Homework Statement:

Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters. A third identical conducting sphere C is uncharged. Sphere C isfirst touched to A, then to B, and finally removed. As a result, the electrostatic force between A and B, which was originally F, becomes:

A. F/2
B. F/4
C. 3F/8
D. F/16
E. 0

Relevant Equations:

F=(Ke*Q*q)/r**2
Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters. A third identical conducting sphere C is uncharged. Sphere C isfirst touched to A, then to B, and finally removed. As a result, the electrostatic force between A and B, which was originally F, becomes:

A. F/2 B. F/4 C. 3F/8 D. F/16 E. 0
 
Last edited by a moderator:

Answers and Replies

  • #2
berkeman
Mentor
57,497
7,524
You are required to post your work toward a solution. What do you think the answer is and why?
 
  • #3
The answer is C). However, I really don't know how to work it out.
 
  • #4
berkeman
Mentor
57,497
7,524
What happens when you touch an isolated neutral object to an isolated charged object? How does the charge divide up and re-distribute?
 

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