The rotor in a certain electric motor is a flat, rectangular coil with 90 turns of wire and dimensions 2.50 cm by 4.00 cm. The rotor rotates in a uniform magnetic field of 0.800 T. When the plane of the rotor is perpendicular to the direction of the magnetic field, it carries a current of 9.1 mA. In this orientation, the magnetic moment of the rotor is directed opposite the magnetic field. The rotor then turns through one-half revolution. This process is repeated to cause the rotor to turn steadily at 3600 rev/min. (a) Find the maximum torque (max) acting on the rotor. Nm (b) Find the peak power output (max) of the motor. W (c) Determine the amount of work (W) performed by the magnetic field on the rotor in every full revolution. J (d) What is the average power (avg) of the motor? I cannot figure out the answer to part D. I know for part A that the torque would equal = (90)(9.1x10-3A)(0.025mx0.04m)(0.800T) = 6.553e-4 Then for part B, it equals the answer to A x 2pi(60) = 0.247W Then part C is given by 4(9.1 x 10-3A)(90)(0.025mx0.04m) = 0.00262J For part D, I thought it would equal part C/(3600/60) ie you know the total work in Joules for a full revolution and now want to divide it by the number of revolutions per second (3600/60)....when I do this on my calculator, I get an answer of 4.3666e-5 The online web program is telling me that I am off by orders of magnitude....but I cannot figure out what I am doing wrong.