Electric Potential and charge flowing between 2 spheres

AI Thread Summary
When a positively charged hollow sphere A at 100 V and a smaller sphere B at 50 V are connected by a wire, charge flows from sphere A to sphere B due to the difference in electric potential. Although the initial assumption is that charge flows from high to low potential, the connection alters the system, resulting in negative charges moving from B to A. This is because, in a conductor, the electric field is zero, leading to a uniform potential throughout. The overall effect is that the potential of sphere A increases as excess charge redistributes. Thus, the final movement of charge is from sphere B to sphere A, confirming the flow of negative charge in the opposite direction of the positive current.
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Homework Statement


A large hollow metallic sphere A is charged positively to a potential of 100 V and a small sphere B to a potential of 50 V. Now B is placed inside A and they are connected by a wire. In which direction will the charge flow?

Homework Equations

The Attempt at a Solution


A is at a higher potential, B at a lower potential. So charge should flow from A to B?
Even if the potentials alter due to the placement of B inside A, A is still at a higher potential?
I don't know the answer, so please confirm?
 
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Positive charge will always flow from high potential to low potential.
 
I just googled this question, and the answer is the opposite, like I'd expected. Charge flows from B to A
 
Notice how I said positive charge?...
 
I like to think of these question with respect to positive charge. Then, when I know what direction positive charge moves, I can simply say: positive charge cannot move, therefore the negative charge must be moving in the opposite direction to make it seem as though the positive charge is moving.
 
I'm fairly confused here, sorry. I'm just talking in terms of positive charges here, so don't worry about negative.
 
By connecting the wire, you are creating a conductor. You know that the electric field anywhere in a conductor is zero. Therefore, the voltage must be constant all throughout the conductor you are now creating. This means that the voltage from the 100V sphere will be reduced and become equivalent all throughout the conductor. Since positive charge cannot move, you know that negative charge will flow from sphere B into sphere A.
 
Oh okay. Thanks :)
 
Since you seem to understand I have only 1 thing to add :)
urgent_mission.png


It took me a while to rectify that electrical current is positive charges flowing.
 
  • #10
Ahhhh, can somebody pleeeeasssseeee just tell me the answer to my question now?

cpscdave said:
Since you seem to understand I have only 1 thing to add :)
urgent_mission.png


It took me a while to rectify that electrical current is positive charges flowing.

That's cute ;)
 
  • #11
All of the excess mobile charge will move to the surface of the outer sphere.
 
  • #12
I'll agree with Luke.Current will flow from A to B but the Negative charge will flow from B-A as negative charges move from lower potential to Higher potential.
For example.Think of a Circuit normally the current flows from higher potential to lower potential (Positive Terminal to Negative Terminal) But if we think the electron would rather move from Negative Terminal to Positive terminal.(opposite charges attract).
 
  • #13
Okay.
 
  • #14
Answer is B-A.End of Story.
 
  • #15
my2cts said:
All of the excess mobile charge will move to the surface of the outer sphere.
my2cts has the correct answer.

The charge on the outer sphere is thus increased and therefore, so is it's potential.
 
  • #16
Sync said:
I'll agree with Luke.Current will flow from A to B but the Negative charge will flow from B-A as negative charges move from lower potential to Higher potential.
For example.Think of a Circuit normally the current flows from higher potential to lower potential (Positive Terminal to Negative Terminal) But if we think the electron would rather move from Negative Terminal to Positive terminal.(opposite charges attract).
Sync said:
Answer is B-A.End of Story.
Sync said:
How to delete the other 3 posts.Can someone help me? I'm new.
Look below your post on the left hand side. There are labels:
"Edit" "Delete" "Report" "Bookmark"

Click on "Delete" and respond appropriately.
[Moderator note: The posts in question were duplicates and have been removed]
 
  • #17
from B to A . since the negative charges will move to high positively charged plate
 
  • #18
What @Luke Cohen , @Dennis Ngeno and @Sync are all missing is that the given potentials were for the case when A and B were separate (and presumably some distance apart). When B is placed inside A, still not connected, the potentials will change. When the two are connected, they become a single conducting solid with a spherical external surface. What do we know about the charge distribution for such? What does the field inside it look like?
 
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