Electric Potential at Center of Uniform Conducting Sphere?

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SUMMARY

The electric potential at the center of a hollow metal sphere is equal to the potential at its surface due to the properties of conductors. In this case, the sphere has a potential of +320 V and a charge of 4.4 x 10-9 C. Since all points inside a conductor are at the same potential, the potential at the center is also +320 V. The charge enclosed within any Gaussian surface inside the conductor remains constant at 4.4 x 10-9 C.

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NeedPhysHelp8
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A hollow metal sphere has a potential of +320 V with respect to ground (defined to be at V = 0) and has a charge of 4.4 x 10-9 C. Find the electric potential at the center of the sphere.

How do you do this. They don't give the radius which would help.
 
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Welcome to PF.

Maybe read this link carefully.
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html#c2

What kind of surface would you construct in the center and how much charge would be enclosed?

Since you are dealing with a conductor and all points inside are at the same potential how much charge can be in the middle?
 
Thanks for the link, but I'm still very confused i don't even know where to start at. You said since its a conductor all points inside have the same electric potential so does this mean that i can find the potential at the surface and be right. And would the charge enclosed just be 4.4 X 10-9 C given in the question. I'm not too sure about what surface you're talking about.
 
NeedPhysHelp8 said:
Thanks for the link, but I'm still very confused i don't even know where to start at. You said since its a conductor all points inside have the same electric potential so does this mean that i can find the potential at the surface and be right. And would the charge enclosed just be 4.4 X 10-9 C given in the question. I'm not too sure about what surface you're talking about.

You have a conductor. So what happens if you put 2 charges together at the center? Will they stay there?
 
Oh nice i got the answer, i just tried entering the voltage they gave me and its the right answer don't know why though
 

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