Electric Potential between two charges of equal magnitude

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SUMMARY

The discussion focuses on determining the electric potential between two charges of equal magnitude Q, positioned a distance d apart. It concludes that there are no points along the line between the charges where the potential is zero when both charges have the same sign. The potential approaches infinity at the location of each charge, making options a and b invalid. The recommended approach includes graphing the potential to visualize its behavior between the charges.

PREREQUISITES
  • Understanding of electric potential (V) and its formula V = k(Q/r)
  • Knowledge of the concept of infinity in mathematical contexts
  • Familiarity with graphing techniques, including using graphing calculators or software
  • Basic principles of electrostatics, particularly regarding point charges
NEXT STEPS
  • Graph the electric potential between two point charges using Microsoft Excel or a graphing calculator
  • Explore the implications of division by zero in the context of electric potential
  • Study the behavior of electric fields around point charges
  • Investigate the concept of superposition in electrostatics
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric potential and its graphical representation between point charges.

wootman23
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Homework Statement


Two charges of equal magnitude Q are held a distance d apart. Consider only points on the line passing through both charges.

If the two charges have the same sign, find the location of all points (if there are any) at which the potential (relative to infinity) is zero.

a) Midway between the charges
b) At the points, where the charges are
c) There are no such points

Homework Equations


V = k(Q/r)

The Attempt at a Solution


I know the answer is not a. But because of the "relative to infinity" statement, I'm not sure about b or c.

For b, the equation would look like: V = k(Q/0) + k(Q/d). I don't know what to do with the division by 0.

I'm inclined to go with c, but I would like some support please.
 
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wootman23 said:
For b, the equation would look like: V = k(Q/0) + k(Q/d). I don't know what to do with the division by 0.
Since the potential approaches infinity at the charge, one simple way to think about the division by 0 is that it is equivalent to infinity.

Even better is to make a graph of the potential, and then look at how the graph behaves in between the charges. You can either hand-sketch a graph, use a graphing calculator if you have one, or perhaps use Microsoft Excel, if your computer has it, to make the graph. You can use anything you want for Q and d, but I suggest trying Q=1 nC (that's 1×10-9 C) and d=1 meter for convenience.
 

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