Electric Potential (Charged Plane)

In summary, the conversation discusses the determination of electric potential at a distance from a large flat metal plate with a uniform distribution of charge. The equations V=V0+Ex and E=σ/ϵ0 are mentioned, but the teacher corrects the understanding of the problem and suggests using |E| = \frac{\sigma}{2\epsilon_0} for the magnitude of the electric field.
  • #1
GDGirl
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0
Teacher explained the solution- thanks!
 
Last edited:
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  • #2
Hi GDGirl,

GDGirl said:

Homework Statement


The electric potential of a very large flat metal plate is Vo = 69 V. It carries a uniform distribution of charge of surface density σ = 0.29 μC/m2. Determine the electric potential V at a distance x = 3.3 cm from the plate. Consider the point at x to be far from the edges, and assume that x is much smaller than the plate dimensions.


Homework Equations


V=V0+Ex

I don't believe this is quite right. Remember that when you move away from positive charges the potential decreases. Do you see what it needs to be?

E=σ/ϵ0

This could be true, but not the way I read the problem. The formula you have here would be true if they meant that the plate was thick and that each side had σ = 0.29 μC/m2. However, if they meant that the plate was thin, then you would have for the magnitude of the electric field:

[tex]
|E| = \frac{\sigma}{2\epsilon_0}
[/tex]

so that might be another problem.
 
  • #3


I am glad to see that you have a good understanding of electric potential and its application to a charged plane. It is essential to have a clear understanding of this concept, as it plays a crucial role in many areas of science and technology, such as electrical engineering and physics.

I would like to add that the electric potential of a charged plane is determined by the distance from the plane and the magnitude of the charge. The closer the distance and the larger the charge, the higher the electric potential will be. This is because the electric potential is a measure of the work done in moving a unit charge from infinity to a specific point in space.

In addition, it is worth noting that the electric potential of a charged plane is constant at all points on the plane. This means that the electric potential does not change as you move along the surface of the plane. This is because the charge is evenly distributed over the plane, resulting in a uniform electric field.

Overall, I am pleased to see your understanding of electric potential and its application to a charged plane. Keep up the good work in your studies, as having a solid understanding of fundamental scientific concepts is essential for any aspiring scientist.
 

1. What is electric potential?

Electric potential is the amount of electrical potential energy that a charged particle has at a certain point in an electric field. It is measured in volts (V) and is a scalar quantity.

2. How is electric potential different from electric potential energy?

Electric potential and electric potential energy are related, but they are not the same thing. Electric potential is the potential energy per unit charge at a specific point, while electric potential energy is the total potential energy of a charged particle due to its position in an electric field.

3. What is a charged plane?

A charged plane, also known as a charged sheet, is a two-dimensional surface that has a uniform distribution of electric charge. It can be positively or negatively charged and is an idealized model used in physics to study the behavior of electric fields and potential.

4. How is electric potential affected by distance from a charged plane?

Electric potential is inversely proportional to the distance from a charged plane. This means that as the distance from the plane increases, the electric potential decreases. This relationship is known as the inverse square law and is a fundamental concept in understanding the behavior of electric fields.

5. How is the electric potential of a charged plane calculated?

The electric potential of a charged plane can be calculated using the equation V = kσ, where V is the electric potential, k is the Coulomb's constant (9 x 10^9 Nm^2/C^2), and σ is the surface charge density (charge per unit area) of the plane. This equation assumes that the plane is infinitely large and has a uniform charge distribution.

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