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GDGirl
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Teacher explained the solution- thanks!
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GDGirl said:Homework Statement
The electric potential of a very large flat metal plate is Vo = 69 V. It carries a uniform distribution of charge of surface density σ = 0.29 μC/m2. Determine the electric potential V at a distance x = 3.3 cm from the plate. Consider the point at x to be far from the edges, and assume that x is much smaller than the plate dimensions.
Homework Equations
V=V0+Ex
E=σ/ϵ0
Electric potential is the amount of electrical potential energy that a charged particle has at a certain point in an electric field. It is measured in volts (V) and is a scalar quantity.
Electric potential and electric potential energy are related, but they are not the same thing. Electric potential is the potential energy per unit charge at a specific point, while electric potential energy is the total potential energy of a charged particle due to its position in an electric field.
A charged plane, also known as a charged sheet, is a two-dimensional surface that has a uniform distribution of electric charge. It can be positively or negatively charged and is an idealized model used in physics to study the behavior of electric fields and potential.
Electric potential is inversely proportional to the distance from a charged plane. This means that as the distance from the plane increases, the electric potential decreases. This relationship is known as the inverse square law and is a fundamental concept in understanding the behavior of electric fields.
The electric potential of a charged plane can be calculated using the equation V = kσ, where V is the electric potential, k is the Coulomb's constant (9 x 10^9 Nm^2/C^2), and σ is the surface charge density (charge per unit area) of the plane. This equation assumes that the plane is infinitely large and has a uniform charge distribution.