GDGirl
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Teacher explained the solution- thanks!
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The electric potential V at a distance x = 3.3 cm from a large flat metal plate with a surface charge density σ = 0.29 μC/m² and an initial potential Vo = 69 V is determined using the equation V = Vo + Ex. The electric field E is calculated using the formula |E| = σ/(2ε₀) for a thin plate, where ε₀ is the permittivity of free space. This approach clarifies that as one moves away from the positive charges, the electric potential decreases, necessitating careful consideration of the plate's thickness in calculations.
PREREQUISITESStudents of physics, educators teaching electrostatics, and anyone interested in understanding electric potential and fields related to charged surfaces.
GDGirl said:Homework Statement
The electric potential of a very large flat metal plate is Vo = 69 V. It carries a uniform distribution of charge of surface density σ = 0.29 μC/m2. Determine the electric potential V at a distance x = 3.3 cm from the plate. Consider the point at x to be far from the edges, and assume that x is much smaller than the plate dimensions.
Homework Equations
V=V0+Ex
E=σ/ϵ0