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Electric Potential (Charged Plane)

  1. Apr 5, 2009 #1
    Teacher explained the solution- thanks!
     
    Last edited: Apr 6, 2009
  2. jcsd
  3. Apr 6, 2009 #2

    alphysicist

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    Homework Helper

    Hi GDGirl,

    I don't believe this is quite right. Remember that when you move away from positive charges the potential decreases. Do you see what it needs to be?

    This could be true, but not the way I read the problem. The formula you have here would be true if they meant that the plate was thick and that each side had σ = 0.29 μC/m2. However, if they meant that the plate was thin, then you would have for the magnitude of the electric field:

    [tex]
    |E| = \frac{\sigma}{2\epsilon_0}
    [/tex]

    so that might be another problem.
     
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