Electric Potential Energy Spherical Shells

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SUMMARY

The discussion focuses on deriving the total electric potential energy of a solid sphere with uniform charge density ρ and total charge Q. The expression for potential energy U is derived using the integral U = ∫4πr²k_e(q/r)dr, where k_e is Coulomb's constant. The charge element dq is defined as dq = 4πr²ρdr, leading to the integration of potential energy contributions from concentric shells. The final expression for the work done to bring a charge from infinity to the sphere is dU = (16/3)π²kρ²R⁴dR.

PREREQUISITES
  • Understanding of electric potential energy and Coulomb's law
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of charge density and its implications in electrostatics
  • Concept of concentric spherical shells in electrostatics
NEXT STEPS
  • Study the derivation of electric potential energy for different charge distributions
  • Learn about the implications of charge density in electrostatic problems
  • Explore advanced integration techniques in physics applications
  • Investigate the role of Coulomb's constant k_e in electrostatic calculations
USEFUL FOR

Students in physics, particularly those studying electrostatics, as well as educators and professionals involved in teaching or applying concepts of electric potential energy and charge distributions.

JosephK
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Homework Statement



A solid sphere of radius R has a uniform charge density ρ and total charge Q. Derive an expression for its total electric potential energy. Suggestion: Imagine that the sphere is constructed by adding successive layers of concentric shells of charge dq = (4\pi r^{2} dr) ρ and let dU = Vdq. (Use any variable or symbol stated above along with the following as necessary: ke.)

Homework Equations



U = \int4\pir^{2}k_{e}\frac{q}{r}dr

\rho=\frac{Q}{\frac{4}{3}\pi r^{3}}



The Attempt at a Solution



The sum of all dq is Q.

U = qV - q is test charge
U = q k_{e}\frac{Q}{r} - equation of voltage substituted

dQ = dq k_{e}\frac{Q}{r} -small potential energy with respect to small charge

dQ = 4k_{e}\pi\rho\frac{Q}{r} r^2 dr - dq plugged in

Then I integrated both sides.
 
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I'm having a little trouble following that.
It seems to me the dQ for the spherical shell is 4πR²ρ*dR.
The work done to bring dQ in from infinity to R is dU = kQ/R*dQ.
And Q up to radius R is 4/3*πR³ρ.
Combined, dU = 16/3π²k ρ²R⁴dR
Check carefully; I make mistakes.
 
Thank you
 

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