Electric potential outside an insulator in a uniform field

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SUMMARY

The discussion focuses on determining the electric potential outside an insulating sphere placed within an Ohmic material with a uniform current density J flowing along the z-axis. The continuity equation and Ohmic material equations are applied, leading to the conclusion that the electric potential outside the sphere must satisfy the Laplace equation, $$\nabla^2V=0$$. The potential at a distance from the sphere is given by $$V_{far}=-\dfrac{J}{\sigma}r\cos\theta$$. The challenge lies in establishing the boundary conditions at the sphere's surface, particularly regarding the behavior of the electric field and current density at the interface.

PREREQUISITES
  • Understanding of Ohmic materials and their properties
  • Familiarity with the continuity equation $$\nabla\cdot J=-\dfrac{\partial\rho}{\partial t}$$
  • Knowledge of Maxwell's equations and boundary conditions
  • Ability to solve the Laplace equation in spherical coordinates
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  • Study the application of boundary conditions in electrostatics
  • Learn about the behavior of electric fields at the interface of different materials
  • Explore the implications of charge density in steady-state conditions
  • Investigate the effects of insulating materials on current flow in conductive media
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Students and professionals in electrical engineering, physicists working with electromagnetism, and anyone studying the behavior of electric fields in materials with varying conductivity.

frimidis
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Homework Statement


An Ohmic material with some conductivity has a uniform current density J initially. Let's say the current is flowing in the direction of the z-axis. A small insulating sphere with radius R is brought inside the material. Find the potential outside the sphere.

Homework Equations


Continuity equation $$\nabla\cdot J=-\dfrac{\partial\rho}{\partial t}$$
Ohmic material electric field $$J=\sigma E$$
Maxwell's equations boundary conditions


$$E_1^{\parallel}-E_2^{\parallel}=0$$


and

$$\epsilon_1E_2^{\perp}-\epsilon_2E_2^{\perp}=\sigma_f$$

Presumably there's no free charge so the charge density of it is 0.

The Attempt at a Solution


I assume the insulator will make the current flow such that there is no change in the charge density. Hence $$\nabla\cdot J=0$$
and so $$\nabla\cdot E=0$$
and so the electric potential obeys the Laplace equation outside the sphere
$$\nabla^2V=0$$

I know the general solution for the Laplace equation in spherical coordinates when there's azimuthal symmetry. I'm stuck with the boundary conditions.

1)
The first one is easy. Far away from the insulator the potential is just due to the electric field that causes the current to flow in the Ohmic material so far away in spherical coordinates
$$V_{far}=-\dfrac{J}{\sigma}z=-\dfrac{J}{\sigma}r\cos\theta$$
2)
I'm unsure about the other boundary conditions. And they seem to be only about the discontinuity of the electric field components at the boundary of the sphere. Apparently we can/need only consider one of the electric field components because we don't have enough information what is going on in the insulator. Is the electric field supposed to be 0 inside it or does it just mean that there doesn't flow any current? I'm stuck at the boundary conditions and I'm not sure how exactly is the current supposed to be affected by the presence of the insulator. Does the current just flow around it tangentially? Presumably no current can go inside as it is an insulator.

Thanks
 
Last edited:
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frimidis said:
2) Does the current just flow around it tangentially? Presumably no current can go inside as it is an insulator.
Yes. In the steady state, any free surface charge on the sphere must be constant in time. What does this tell you about the radial component of ##\vec J## at the outside surface of the sphere? In turn, what boundary condition on ##V## does this imply at the outside surface of the sphere?
 

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