Electric potential problem ?

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When an earthed rod is brought near a positively charged electroscope, the electric potential of the electroscope decreases due to induced charges. The positive charge on the electroscope attracts electrons to the rod, creating a negative charge at its tip. This negative charge repels electrons from the electroscope's disc, causing the leaves to collapse slightly. Despite the electroscope being positively charged, it still contains some electrons, as only a fraction of them are removed during charging. The interaction can lead to various phenomena, such as sparks and discharges, before inner electrons are affected.
ngkamsengpeter
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I want to know that why electric potential of the electroscope which is charge positive decrease when a rod which is earthed is brought near to the electroscope .
 
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Well an intuitive explanation for this is that the positive charge on the electroscope will induce a negative charge on the rod, that is it draws some electrons onto the tip of the rod closest to the electroscope. The presence of this negative charge on the rod will repel electrons from the disc at the top of the electroscope downwards towards the leaves of the electroscope thereby causing them to collapse a bit.
 
andrevdh said:
Well an intuitive explanation for this is that the positive charge on the electroscope will induce a negative charge on the rod, that is it draws some electrons onto the tip of the rod closest to the electroscope. The presence of this negative charge on the rod will repel electrons from the disc at the top of the electroscope downwards towards the leaves of the electroscope thereby causing them to collapse a bit.
But I mentioned that the electroscope is charged positive so there should be no electron on the electroscope right ?
 
Only a slight charge imbalance (different amounts of positive and negative) is created in a body when it is charged up, in this case only a fraction of the electrons on the surface of the conducting part of the electroscope is removed. This involves some of the "outer" conduction electrons of the atoms. There will still be plenty of electrons left in the material. It takes quite a lot of energy to strip the inner electrons off the atoms. So the conduction electrons will be removed gradualy as it is charged up. Long before the inner ones are ripped out of the atoms all sorts of phenomena will start to manifest like sparks, discharges in the air and glowing light around the charged object.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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