Electric Potential: Two Spherical Shells

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SUMMARY

The discussion centers on calculating the electric potential at a distance of 0.15 m from a point charge surrounded by two conducting spherical shells. The inner shell is uncharged, while the outer shell has a net charge of -10 µC. The potential at infinity is given as 1.4 x 10^5 V. The correct approach involves summing the potentials across the shells and incorporating the specified potential at infinity to find V(0.15 m).

PREREQUISITES
  • Understanding of electric potential and its relationship with electric fields
  • Knowledge of spherical shell charge distributions
  • Familiarity with integration in electrostatics
  • Proficiency in using the formula Vb - Va = ∫E∙dl
NEXT STEPS
  • Study the concept of electric potential in spherical coordinates
  • Learn about the properties of conducting materials in electrostatics
  • Explore the implications of charge distribution on electric potential
  • Review advanced integration techniques for calculating potentials
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone studying electrostatics or electric potential in conductive materials.

Bryon
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Homework Statement


A point charge q = -8 µC is surrounded by two thick, conducting spherical shells of inner and outer radii a1 = 0.3 m, a2 = 0.4 m, a3 = 0.7 m, and a4 = 0.8 m respectively. The inner shell is uncharged; the outer shell has a net charge Q = -10 µC. At this point in the problem, the potential at infinity is unspecified.

Homework Equations


Vb - Va = ∫E∙dl = kQ(1/b - 1/a)

The Attempt at a Solution



Va4 - Vinf[/SUB] = -202275V OK
Va3 - Va4 = 0V OK
Va2 - Va3 = -77057.14286V OK
Va1 - Va2 = 0V OK
V(0.15) - Va1 = -239733.3333V

The final part of the problem asks this:

If now you are given V(inf) = 1.4 x 10^5 V, find the potential at r = 0.15 m.

I tried to do it like this:

-237933.333V + 1.4x10^5 = -99733.3333V which is incorrect. Do I have to go and find each one with respect to v(inf) = 1.4x10^5? Or do I need to find the total charge of the outermost shell and then find the potential from there to 0.15m?
 
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-237933.333V + 1.4x105 V = V(0.15) - Va1 + V, which isn't what you want.

It appears to me that what's being asked for is V(0.15) ‒ V .

You need (V(0.15) ‒ Va1) + (Va1 ‒ Va2) + (Va2 ‒ Va3) + (Va3 ‒ Va4) + (Va4 ‒ V).

I believe that your first answer, Va4 - Vinf[/sub] = -202275V, assumed that the potential at infinity was unspecified, so you used zero.
 

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