Electric power transformer problem

Click For Summary
SUMMARY

The discussion focuses on the calculation of power loss in electric transmission lines, specifically when transmitting 120 kW of power at 240 V over a distance of 10 km with a total resistance of 0.40 ohms. The calculated current is 500 A, leading to a power loss of 100 kW using the formula P(loss) = I²R. The confusion arises from the interpretation of power loss, which is attributed to the heat generated in the wires due to resistance, rather than a simple subtraction of input and output power.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with power calculations in electrical engineering
  • Knowledge of electrical resistance and its effects
  • Basic concepts of power transmission systems
NEXT STEPS
  • Study the derivation of Ohm's Law and its applications in power systems
  • Learn about power loss calculations in transmission lines
  • Explore the effects of resistance on power efficiency in electrical systems
  • Investigate methods to minimize power loss in electrical transmission
USEFUL FOR

Electrical engineers, power system analysts, and students studying electrical transmission and power loss calculations will benefit from this discussion.

MIA6
Messages
231
Reaction score
0
An average of 120 kW of electric power is sent to a small town from a power plant 10 km away. The transmission lines have a total resistance of 0.40 ohms. Calculate the power loss if the power is transmitted at 240 V.
The solution is I=P/V=500 A, then the power loss in the lines, P(loss)=I^2R=(500A)^2*0.04ohms=100kW
Here I don't understand why Ploss=I^2*R? I mean is that supposed to be power output, so then in order to find the power loss, we need to use Power input 120kW-output 100kW, then 20 is the power loss?! Because when I see 'loss', it's like a common sense to use subtraction, but how come here is not? thanks for help.
 
Physics news on Phys.org
It's called power loss because the 100kW is due to the heating of the wire because of the wire's resistance; that heat is lost to the air (and therefore not available for use).


Since you mentioned subtraction, to see how subtraction could be involved: If the 120kW is what the power plant generates, then we have

120kW - generated by power plant
100kW - lost as heat in the wire between the power plant and the city
20kW - power available to the city

so if you somehow knew ahead of the time the power available to the city then you could subtract that from the power generated by the power plant to find the power loss.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K