Power in a simple electric circuit

Karol
Messages
1,380
Reaction score
22

Homework Statement


A circuit consists of a battery with internal resistance r and a resistor with resistance R.
It has been found that the maximum power generated is when R=r.
Prove that in those conditions ##P_{max}=\frac{ε^2}{4r}##

Homework Equations


Power invested in a resistor: P=i2R
Power invested between 2 points in a circuit: P=Vi

The Attempt at a Solution


The current: ##i=\frac{V}{2r}##
Voltage drop on the internal resistance: ##V=ir=\frac{V}{2}##
Power between the terminals of the battery: ##P=iV=\frac{V}{2r} \frac{V}{2}=\frac{V^2}{4r}##
But the power loss on one resistor (the internal or the external):
$$P=i^2r=\frac{V^2}{4r^2}\cdot r=\frac{V^2}{4r}$$
It's identical to the total power, and there are 2 resistors so they consume double the power, how come?
 
on Phys.org
Karol said:
It's identical to the total power, and there are 2 resistors so they consume double the power, how come?
The total power delivered by the battery is the current times the battery EMF (which is V), not the terminal voltage (V/2).
 
So:
$$P_{max}=\varepsilon\cdot i=\varepsilon\cdot \frac{\varepsilon}{2r}=\frac{\varepsilon^2}{2r}$$
The book asked about the maximum power of the battery and i guess this is the answer. the answer of the book is:
$$P_{max}=\frac{\varepsilon^2}{4r}$$
 
Karol said:
So:
$$P_{max}=\varepsilon\cdot i=\varepsilon\cdot \frac{\varepsilon}{2r}=\frac{\varepsilon^2}{2r}$$
The book asked about the maximum power of the battery and i guess this is the answer. the answer of the book is:
$$P_{max}=\frac{\varepsilon^2}{4r}$$

The maximum power the question is asking about is the maximum power delivered to the load, that's the external resistor only.
 
Thanks, i guess you are right. but is there, in general, a meaning to the multiplication of the terminals of the battery voltage and the current P=V⋅i? not in this specific problem but in general. i guess it's the power delivered to the rest of the circuit, right?
 
Last edited:
Karol said:
Thanks, i guess you are right. but is there, in general, a meaning to the multiplication of the terminals of the battery voltage and the current P=V⋅i? not in this specific problem but in general. i guess it's the power delivered to the rest of the circuit, right?
Yes. That's the power that the battery is delivering [to the external circuit]. In this problem, and in general.
 
Je Suis Charlie also, thanks
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 49 ·
2
Replies
49
Views
8K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
1
Views
2K