Electric Power: V^2/ohm Has SI Units of Power

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SUMMARY

The discussion confirms that the quantity volts squared per ohm (V²/Ω) indeed has SI units of power, specifically watts (W). This conclusion is derived from the power formula P = V x I, where Ohm's law (I = V/R) is applied to express power in terms of voltage and resistance. The derivation shows that P = V²/R, leading to the equivalence of watts with V²/Ω. Additionally, the relationship between volts, joules, and charge further substantiates that V²/Ω equals joules per second, reinforcing the definition of power.

PREREQUISITES
  • Understanding of electrical power formulas, specifically P = V x I.
  • Familiarity with Ohm's law and its components (voltage, current, resistance).
  • Knowledge of SI units, particularly the definitions of volts, ohms, and watts.
  • Basic concepts of energy, work, and charge in electrical systems.
NEXT STEPS
  • Study the derivation of electrical power formulas in depth, focusing on P = V²/R.
  • Explore the implications of Ohm's law in circuit analysis.
  • Learn about the relationship between energy, work, and electrical units in practical applications.
  • Investigate advanced electrical concepts such as reactive power and its relation to impedance.
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Electrical engineers, physics students, and anyone interested in understanding the principles of electrical power and its calculations.

predentalgirl1
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Show the quantity volts squared per ohm (V^2/ohm) has SI units of power.








P = V x I
where
P is the power (watt or W)
V is the potential difference (volt or V)
I is the current (ampere or A)
From Ohm’s law
I = V / R
where
R is the resistance (Ohm or Ω).
So substituting in the above equation
P = V x (V/R)
P = V2 /R
So in unit , watt = (volt)2 / Ω


OR
I can rewrite, V^2/R = V.V/R = V.I
From definition of potential difference as Work done per unit charge, V = W/q
Unit volt, V = unit of W/unitof chaarge = J/C
Also current = charge/time
I = C/s
so, V^2/R = V.V/R = V.I
= J/C xC/s = J/s
= watt, (unit of power.)


Which seems most reasonable?
 
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You should use the 2nd one as that uses what they gave you V^2/omega to get J/s.
 

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