Electrical charge problem (need assurance on an answer)

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SUMMARY

The discussion centers on calculating the maximum charge that can be stored on a green pea before it discharges due to an electric field exceeding 3.0 × 106 N/C. The relevant equation used is E = kQ/r2, leading to the formula Q = Er2/k. After correcting the radius to 0.405 cm, the final calculated charge is approximately 5.5 × 10-9 C, confirming the accuracy of the solution provided by the user ehild.

PREREQUISITES
  • Understanding of electric fields and their breakdown thresholds
  • Familiarity with Coulomb's law and the constant k (Coulomb's constant)
  • Ability to perform unit conversions (cm to m)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the implications of electric field strength in different materials
  • Learn about Coulomb's law and its applications in electrostatics
  • Explore the concept of dielectric breakdown in gases
  • Investigate the effects of charge distribution on small objects
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in electrostatics and charge behavior in small objects.

AyooNisto
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Homework Statement



Dry air will break down and generate a spark if the electric field exceeds about 3.0\times 10^6 N/C How much charge could be packed onto a green pea (diameter 0.81cm ) before the pea spontaneously discharges?

Homework Equations



E = kQ/r^2
Q = Er^2/ k <-------this is the equation to use I believe

The Attempt at a Solution


(3*106)(3.81*10-3)2/8.988*109

resulting in an answer of 4.845160214*10-9 = 5*10-9

does this look right to you guys?
 
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The radius is not 3.81*10-3 m. Check.

ehild
 
figured it out, the diameter is .405
so the answer would be
(3*106)(4.05*10-3)2/8.988*109 = 5.5 *10^-9
Thank you for your help
ehild said:
The radius is not 3.81*10-3 m. Check.

ehild
 

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