Electrical Engineering - Increasing the Time an Alarm will Buzz

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Discussion Overview

The discussion revolves around designing an alarm circuit that buzzes for approximately 6 seconds. Participants are exploring circuit configurations, component values, and calculations related to the timing of the buzzer. The scope includes theoretical and practical aspects of electrical engineering, particularly in relation to circuit design and component behavior.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant describes their attempt to create an alarm that buzzes for 6 seconds, noting that their current design only buzzes for about 1.5 seconds.
  • Another participant questions the buzzer's connection and operation within the circuit, suggesting the use of an NPN transistor to drive the buzzer.
  • A participant mentions a calculation for Thevenin voltage and time constant, proposing values for these parameters and suggesting a capacitor value.
  • There is a suggestion to use a normally open switch in series with the buzzer and capacitor, questioning the current approach taken by the original poster.
  • Some participants express confusion about specific voltage values used in calculations and their relevance to the buzzer's operation.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best approach to achieve the desired buzzing duration. Multiple competing views and suggestions are presented, and the discussion remains unresolved regarding the optimal circuit design.

Contextual Notes

There are uncertainties regarding the assumptions made in calculations, the definitions of circuit parameters, and the specific configurations of components in the proposed designs. Some participants express confusion about the voltage values and their implications for the buzzer's operation.

Mosaness
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Homework Statement



The problem is to create a small alarm that will buzz approximately 6 seconds before it stops buzzing. I managed to create a working alarm, only problem is mines will buzz for around 1.5 seconds not six.

Homework Equations



τ = RC
V = V0e-t/τ


The Attempt at a Solution



Req. = 400Ω + (80Ωll100Ω) ≈ 444.44 Ω
VTH = 6V * (400Ω/480Ω) = 5V

Substituting this into equation #2 above gives 5V = 9V*e-6/τ
Solving for T yields:

Actually, I just lost myself in my work. Can someone help me.
 

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Mosaness said:

Homework Statement



The problem is to create a small alarm that will buzz approximately 6 seconds before it stops buzzing. I managed to create a working alarm, only problem is mines will buzz for around 1.5 seconds not six.

Homework Equations



τ = RC
V = V0e-t/τ


The Attempt at a Solution



Req. = 400Ω + (80Ωll100Ω) ≈ 444.44 Ω
VTH = 6V * (400Ω/480Ω) = 5V

Substituting this into equation #2 above gives 5V = 9V*e-6/τ
Solving for T yields:

Actually, I just lost myself in my work. Can someone help me.

Where is the buzzer? How is it turned on and off?
 
berkeman said:
Where is the buzzer? How is it turned on and off?

The buzzer has a resistance of 400 ohms so that's what was used. It is turned on when someone opens the window.
 
Mosaness said:
The buzzer has a resistance of 400 ohms so that's what was used. It is turned on when someone opens the window.

And how do you intend to connect the buzzer and window switch to your circuit that you've drawn? How does the circuit reset when the window is later closed?

BTW, it would be better to use an NPN transistor as part of the circuit that drives the buzzer. Do you know why?
 
berkeman said:
And how do you intend to connect the buzzer and window switch to your circuit that you've drawn? How does the circuit reset when the window is later closed?

BTW, it would be better to use an NPN transistor as part of the circuit that drives the buzzer. Do you know why?

Oh...the class I am taking is a basic class. I've never even heard of a NPN transistor. I made a PSPICE design. The switch was connected right next to the 100Ω.
 
I did a calculation earlier but I slightly messed up. I obtained Vthevenin by the equation 18V * 80/180 --> which gave me 8V.

I then set that so:

8V = 18V*e^-6/tau and solved for tau, which gave me tau = 7.3989

Using that tau I solved for C, which gave me C = .0166 F
 
Mosaness said:
I did a calculation earlier but I slightly messed up. I obtained Vthevenin by the equation 18V * 80/180 --> which gave me 8V.

I then set that so:

8V = 18V*e^-6/tau and solved for tau, which gave me tau = 7.3989

Using that tau I solved for C, which gave me C = .0166 F

Why not just use a "normally open" (NO) switch in series with the buzzer, a resistor and a cap? Or even just the switch, buzzer and cap...?
 
berkeman said:
Why not just use a "normally open" (NO) switch in series with the buzzer, a resistor and a cap? Or even just the switch, buzzer and cap...?

Well I just went on the way I know a few people did. And that seems to be giving me an appropriate time...
 
Mosaness said:
Req. = 400Ω + (80Ωll100Ω) ≈ 444.44 Ω
VTH = 6V * (400Ω/480Ω) = 5V

Substituting this into equation #2 above gives 5V = 9V*e-6/τ
Req I understand. VTH I don't.

According to your schematic, you are using a supply voltage of 18V. Correct? So where did the "6V" figure come from? What is special about the "5V" figure? Where did the "9V" come from? What operating parameter of the buzzer are you working with, in trying to determine how long it will actually "buzz"?
 

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