Electrical flux passing through the cube

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Homework Help Overview

The discussion revolves around the concept of electric flux and its calculation through a cube, specifically using Gauss's law. Participants are exploring how to approach the problem without relying on cylindrical symmetry, focusing instead on the properties of the cube and its sides.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning how to apply Gauss's law to a cube and whether the relevant equations are dependent on the shape of the surface. There is a discussion about integrating the flux and the implications of symmetry in the electric field.

Discussion Status

The discussion is ongoing, with participants seeking clarification on relevant equations and the relationship between surface shape and electric flux. Some guidance has been offered regarding the application of Gauss's law, but multiple interpretations are still being explored.

Contextual Notes

There is an emphasis on solving the problem without using cylindrical coordinates, which may limit the approaches discussed. Participants are also considering the implications of symmetry in their reasoning.

MatinSAR
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Homework Statement
Consider a rod with an electric charge density λ that passes through the center of the cube. Prove that the electric flux passing through this cube is equal to = q / ε0
Relevant Equations
Gauss's law
1647210501510.png

Picture for better understanding.
My answer :
1647211185819.png


I want to know how to solve this problem without using cylindrical. I mean how can we solve this using cube and its sides.
Thanks.
 
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MatinSAR said:
Relevant Equations:: Gauss's law

I want to know how to solve this problem without using cylindrical. I mean how can we solve this using cube and its sides.

What about your relevant equation ?

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BvU said:
What about your relevant equation ?

##\ ##
Thank you ... but what do you mean by relevant equation?
 
Does your relevant equation worry about the shape of the surface ?

[edit]On the other hand,
Prove that the electric flux passing through this cube is equal to = q / ε0
could be interpreted as an invitation to show that for this case the gauss identity holds. In that case you could actually integrate the flux: you know the electric field (right?) and can benefit from symmetry.

##\ ##
 
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BvU said:
Does your relevant equation worry about the shape of the surface ?
I guess no it doesn't ... Thank you for your help ...
 
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