Electrical Potential at point Y between 2 point charges

1. Apr 23, 2012

BN Joe

1. The problem statement, all variables and given/known data

Two charges, one of charge +1.5 x 10^–2 C and the other of charge –2.7 x 10^5 C, are 20.0 cm apart. The positive charge is to the left of the negative charge.
(a)Draw a diagram showing the point charges and label a point Y that is 5.0 cm away from the positive charge, on the line connecting the charge and between the two charges. (Field lines need not be drawn.)
(b)Calculate the electric field at point Y.
(c)Calculate the electric potential at point Y

q1 = 1.5 x 10^-2 C
q2 = -2.7 x 10^-5 C
d = 0.2m
k = 9 x 10^9

2. Relevant equations

Not sure... possibly
v = kq1 / d

3. The attempt at a solution

I had no issues with parts a and b, but I am not sure of the correct formula to solve part c and the answer I got doesn't seem to make sense.
If it helps the electric field at point y is 5.4 x 10^10 N/C

V = kq1 / d
v1 = (9 x 10^9)(1.5 x 10^-2C) / 0.05m
= 2.7 x 10^9
v2 = (9 x 10^9)(-2.7 x 10^-5C) / 0.15m
= -1.62 x 10^6
Vtotal = v1 + v2
= 2.7 x 10^9 V

2. Apr 23, 2012

Staff: Mentor

Your calculations look fine.

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