Electricffiledcalcuate escape speed

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    Escape Speed
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SUMMARY

The discussion centers on calculating the escape speed in an electric field, specifically using the equations for kinetic energy (KE) and electric potential energy (Ue). The key formulas referenced include KE = 1/2 mv² and Ue = Eqs, leading to the conclusion that the escape speed (v) can be derived as v = (sEqs/m)^(1/2). The final answer provided is 2.3 x 10^6 m/s, confirming the calculation's accuracy.

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electricffiled..calcuate escape speed! urgent please help

Homework Statement



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Homework Equations



ke=1/2mv^2
Ue=Eqs
E=kq/r^2

The Attempt at a Solution


Uf+kf=Ki+Ui

Uf=0 and Kf=0

so -Ui=Ki
Eqs=1/2(mv^2)

v=(sEqs/m)^1/2 after this no clue i got lost help please
 
Last edited:
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sry guys is the answer 2.3x10^6m/s
 


Yes, it is.

ehild
 

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