Electricity Help: 25 Ah Battery & 8 kW Shower Heater

  • Thread starter Thread starter CathyLou
  • Start date Start date
  • Tags Tags
    Electricity
Click For Summary

Homework Help Overview

The discussion revolves around electricity concepts, specifically focusing on a 25 Ah battery and an 8 kW shower heater. The original poster seeks assistance in calculating the number of available electrons in the battery and the number of electrons passing through the heater over a specified time period.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to find the charge moving in each scenario and how to convert the battery's capacity from Amp Hours to seconds. There are questions about the correct method for this conversion and the relationship between charge, current, and time.

Discussion Status

Participants are actively engaging with the problem, offering insights into the calculations needed. Some guidance has been provided regarding the conversion of time and the interpretation of Amp Hours, but there is no explicit consensus on the methods to be used.

Contextual Notes

There is a noted confusion regarding the conversion of Amp Hours to seconds and the charge on an electron. The original poster is working within the constraints of homework rules that require them to derive the answers independently.

CathyLou
Messages
173
Reaction score
1
Hiya.

I'm really struggling with the following electricity questions and so any help would be very much appreciated.

How many available electrons are there in a 25 Ah battery?

How many electrons pass through a 240 V mains shower heater of 8 kW if it is on for 5 minutes?


Thank you.

Cathy
 
Physics news on Phys.org
You have to find the charge moving/transferring in each case first then convert this knowing the charge on an electron.

So, you need the formula that links charge, current and time (and watch out, your battery is given in Amps Hours and you'll need it in seconds)
 
rsk said:
You have to find the charge moving/transferring in each case first then convert this knowing the charge on an electron.

So, you need the formula that links charge, current and time (and watch out, your battery is given in Amps Hours and you'll need it in seconds)

Thanks for replying.

To convert the battery from Amp Hours to seconds, do I just divide 25 by 60?

I know that I = Q / t and that the charge on an electron is 1.6 x 10^-1, but I'm still not sure how to get an answer to the first question.

Cathy
 
No, I think you'd multiply by 60x60.

I think 25Ah means it can give 25 amps for 1 hour (or 1 amp for 25 hours or any number of other combinations) so it will give 25 amps for 60x60 seconds.

That will give you the total charge available - and since you know the charge on each electron, just divide by that to find out how many electrons.
 
rsk said:
No, I think you'd multiply by 60x60.

I think 25Ah means it can give 25 amps for 1 hour (or 1 amp for 25 hours or any number of other combinations) so it will give 25 amps for 60x60 seconds.

That will give you the total charge available - and since you know the charge on each electron, just divide by that to find out how many electrons.

Okay. Thanks for your help!
 

Similar threads

Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
11
Views
14K
  • · Replies 6 ·
Replies
6
Views
10K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
16K