Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Current drawn from car battery to heat up water

  1. Feb 13, 2006 #1
    A small immersion heater can be used in a car to heat a cup of water for coffee or tea. If the heater can heat 120 mL of water from 25 C to 95 C in 8 minutes, a) approximately how much current does it draw from the car's 12-V battery, and b) what is its reistance? Assume the manufacturer's claim of 60% efficiency.

    My work:

    T(f) - 95 C T(i)= 25 C
    t = 8 min = 480 s
    V= 12 V
    volume = .12 L

    First I converted .12 L to kg using density of water, comes out .12 kg.

    Then I used the relationship between heat transfer and temperature change equation Q= mcT, specific heat of water is 4186 J/kg Cel

    Q = .12kg (4186 J/kgC) (95 C-25 C) = 35162.4 J to heat the water.

    Then I used the power equation, Power = work/time = 35162.4 J / 480 s = 73 Watts

    Then I used I = P/V, Electric Current = Power / voltage = 73 W/12 V = 6.1 A

    The answer in the back of the book says 10 A. I got 6.1 A, which if rounded up could be 10 A and it does say approximately, but I'm not sure if I did this right at all and if my work is wrong he will check it wrong. Am I doing this right or wrong? If wrong, what should I do?? And I'm not sure where the efficiency comes in? Thanks for any help
     
  2. jcsd
  3. Feb 13, 2006 #2

    andrevdh

    User Avatar
    Homework Helper

    Only 60% of the input power (or energy) is converted to heat by the resistor, that is
    [tex]0.6P_{input}=P_{resistor}[/tex]
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook