What ions produce a 2.00 V potential in an electrochemical cell?

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SUMMARY

The discussion focuses on constructing an electrochemical cell that produces a potential closest to 2.00 V using specific ions. The proposed reactions are Fe3+ to Fe2+ with a standard reduction potential of -0.771 V and Na(s) to Na+ with a standard oxidation potential of +2.71 V. The calculated cell voltage from these reactions is 1.94 V, which is close to the target of 2.00 V. The discussion emphasizes the importance of correctly applying the signs of the voltages when combining reactions.

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Homework Statement


Based on the following chart, what ions would you use to construct an electrochemical cell with potential closest to 2.00 V?

[PLAIN]http://img546.imageshack.us/img546/5568/electrochemicalcellchar.png

Homework Equations


I know that I am supposed to add the voltages of the 2 reactions but I am not sure how the signs would go. We are not using a textbook for this class so I have nothing to reference.


The Attempt at a Solution


I'd use the following reactions and voltages
Fe3+ -> Fe2+ (-0.771 gaining electron)
Na (s) -> Na+ (+2.71 losing electron)

so the cell voltage would be 1.94V. Is this correct?
 
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Think about simple math - what is the distance between -2.7 and +0.7 points?
 
Thank you, that was very helpful!
 

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