Electrolysis of Water: Calculating Current

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SUMMARY

The discussion focuses on calculating current during the electrolysis of water using a 9V battery. Participants emphasize the importance of measuring resistance with electrodes submerged in water to determine current flow. The presence of gas bubbles generated during electrolysis complicates current predictions, as they interfere with conduction. For resistivity experiments without gas formation, using low-voltage AC is recommended instead of DC from a battery.

PREREQUISITES
  • Understanding of electrolysis principles
  • Knowledge of Ohm's Law (Volts = Current x Resistance)
  • Experience with measuring electrical resistance
  • Familiarity with the effects of gas bubbles on conductivity
NEXT STEPS
  • Research methods for measuring resistance in electrolytic solutions
  • Learn about the effects of electrode surface area on electrolysis efficiency
  • Explore low-voltage AC applications in resistivity experiments
  • Investigate techniques for bubble removal during electrolysis
USEFUL FOR

Students, hobbyists, and professionals interested in electrolysis, electrical engineering, and experimental physics will benefit from this discussion.

lasha1
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I want to know how to conduct I ampere current through solution.
For example i have 9V battery and 1 liter of water and i conducted electricity through water. How to calculate the current ?
 
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If t is useful. For example during 1 hour.
 
Volts = current x resistance. Measure the resistance on your electrodes.
 
With the electrodes placed in the water, and the battery disconnected, measure the resistance of the circuit.
 
lasha1 said:
I want to know how to conduct I ampere current through solution.
For example i have 9V battery and 1 liter of water and i conducted electricity through water. How to calculate the current ?
Predicting the current is not possible. I presume you will add electrolyte so some water dissociates to gases? As soon as DC flows bubbles of gas start to accumulate on the electrodes and this interferes with their conduction of current into the solution. For more current, you can try larger electrodes with their larger surface area, but these, too, will become coated with gas. You can agitate the vessel or components to try to dislodge some bubbles and the situation certainly reaches an equilibrium, but I don't think it is easily predicted.

If you are wanting to avoid gas forming on the electrodes, and just do resistivity experiments, you'll need to use low-voltage AC instead of the battery.

Good luck!
 
Thanks guys
 

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