Can Current Density Static Create an Effective Electromagnetic Shield?

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SUMMARY

The discussion centers on the effectiveness of static current density in creating an electromagnetic shield. Participants clarify that simply holding the current density static does not effectively block electromagnetic radiation, as fields add vectorially, and a static field does not shield against dynamic fields. The Faraday cage is highlighted as a proven method for electromagnetic shielding, where charges on the surface of the conductor reorient to create an opposing field that blocks external electromagnetic waves. The conversation emphasizes the importance of understanding established principles like Maxwell's equations and the operational mechanics of a Faraday cage.

PREREQUISITES
  • Understanding of Maxwell's equations
  • Knowledge of electromagnetic fields and their properties
  • Familiarity with the concept of a Faraday cage
  • Basic principles of electromagnetic radiation
NEXT STEPS
  • Study the operational principles of Faraday cages in detail
  • Explore the implications of Maxwell's equations in electromagnetic theory
  • Investigate the behavior of electromagnetic waves in waveguides
  • Learn about the vector addition of electric fields and their shielding effects
USEFUL FOR

Electromagnetic engineers, physicists, and anyone involved in designing or analyzing electromagnetic shielding solutions will benefit from this discussion.

cuallito
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I've been thinking about electromagnetic shielding lately.

Of course, you have your good, old-fashioned Faraday cage.

But after staring at Maxwell's equations awhile, I'm thinking:

We're after a static E field, right?

So if we set ## \frac{\partial \textbf{E}}{\partial t}=0## in Ampere's Law, we get

$$\nabla\times \textbf{B}=\mu_0 \textbf{J}$$

Implying that if we can hold the current density ##\textbf{J}## static around a region of space, say with a constant current source, we'd effectively 'fix' the field in that region of space, thus blocking out any incident EM radiation (theoretically)?

For example, if we had a cylinder wrapped around in conducting wire, hooked up to a constant current source, would the field in the interior of the cylinder stay static regardless of what the field outside it was doing?
 
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cuallito said:
We're after a static E field, right?
No. We are after shielding against electromagnetic radiation.

cuallito said:
Implying that if we can hold the current density J static around a region of space, say with a constant current source, we'd effectively 'fix' the field in that region of space, thus blocking out any incident EM radiation (theoretically)?
No. It is not implying that and I am not sure how you arrived at such a conclusion.

cuallito said:
For example, if we had a cylinder wrapped around in conducting wire, hooked up to a constant current source, would the field in the interior of the cylinder stay static regardless of what the field outside it was doing?
No.

Perhaps it would be beneficial to first understand how a Faraday cage works.
 
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cuallito said:
Implying that if we can hold the current J density static around a region of space, say with a constant current source, we'd effectively 'fix' the field in that region of space, thus blocking out any incident EM radiation (theoretically)?
Fields add vectorally, so adding a static field does nothing to "shield" other fields that are present. It just adds a DC field term to the vector sum.
 
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cuallito said:
I've been thinking about electromagnetic shielding lately.

Of course, you have your good, old-fashioned Faraday cage.

But after staring at Maxwell's equations awhile, I'm thinking:

We're after a static E field, right?

So if we set ## \frac{\partial \textbf{E}}{\partial t}=0## in Ampere's Law, we get

$$\nabla\times \textbf{B}=\mu_0 \textbf{J}$$

Implying that if we can hold the current density ##\textbf{J}## static around a region of space, say with a constant current source, we'd effectively 'fix' the field in that region of space, thus blocking out any incident EM radiation (theoretically)?

For example, if we had a cylinder wrapped around in conducting wire, hooked up to a constant current source, would the field in the interior of the cylinder stay static regardless of what the field outside it was doing?
A Faraday cage is essentially the same as a mirror for visible light frequencies. The way it shields is the charges present on the surface of the conducting shield reorient in response to the external field, this causes an equal and opposite field to appear at the surface of the shield which blocks the primary EM that tries to propagate through.

Somewhat the same way a waveguide for RF frequencies work. The RF wave doesn't get outside the enclosed guide because the inner walls are conducting and they reflect the wave everytime it hits the walls , which it does so after even distances which are related to the wavelength of the wave
 

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