Electromagnetic waves and astronaut

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Homework Help Overview

The problem involves an astronaut using a flashlight as a propulsion method to reach a space shuttle while floating in space. The context is rooted in concepts of electromagnetic waves and momentum, specifically relating to the use of light as a means of generating thrust.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of the equation E=c*p to relate energy, momentum, and the speed of light. There are attempts to calculate the resulting velocity and time taken to reach the shuttle, with various intermediate calculations being shared.

Discussion Status

Some participants have provided calculations and results, while others have pointed out potential errors in reasoning or calculation methods. There is an ongoing exploration of the relationship between power, force, and acceleration, with no clear consensus on the correct approach yet.

Contextual Notes

Participants are working under the constraints of a homework problem, which may limit the information available and the methods they can use. There is a noted confusion regarding the application of physical principles and the resulting calculations.

yogi41
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Homework Statement



I've been trying to do this problem for about 2 hours now. I can't seem to find the right equations to use. Any help would be appreciated

A spacewalking astronaut servicing an orbiting space telescope has run out of fuel for her jet pack and is floating 20.0 m from the space shuttle with zero velocity relative to the shuttle. The astronaut and all her gear have a total mass of 150kg. If she uses her 220w flashlight as a "light rocket," how long will it take her to reach the shuttle?

Homework Equations





The Attempt at a Solution

 
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How about this one, E=c*p. Where E is the energy of the light beam, p is it's momentum and c=speed of light.
 
the answer is supposed to be 25.1 hours. When i used E=c*p i ended up getting 1250000 hours. Am i doing a simple calculation wrong?
 
I get the 25 hour figure as well. Did you compute the force exerted by the beam? What are some of your intermediate results?
 
well i first calculated p 220w/3x10^8 which was 7.33 x 10^-7
then i divided that answer by 150kg to get 4.89 x 10^-9 which I'm assuming is my velocity
from there i divided the distance from the ship which was 20m to get 2.44 x 10^-10
and then i divided 1/2.44 x 10^-10 to get my answer in seconds
 
Keep track of units. Then you won't have to 'assume' that something is a velocity. Power/c is a force. (Power/c)/mass is an acceleration. Not a velocity.
 
Last edited:
so I took the square root of the 2.44 x 10^-10 1/s^2 to get 1.56 x 10^-5 1/s and i flipped the sign by 1/1.56 x 10^-5 1/s to get 64018.4 but then when i convert it back to hours it's only 17.8 hours when it is supposed to be 25.1 hours. Where did i make the mistake? thanks for the help
 
The relation between distance, time and acceleration is d=(1/2)*a*t^2. Looks like you dropped the (1/2).
 

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