Momentum in Space - How long will it take?

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SUMMARY

The discussion centers on calculating the time it takes for a 66kg astronaut to return to her shuttle after being separated in space. By throwing a 0.912kg camera at a speed of 12m/s, the astronaut utilizes the principle of conservation of momentum, resulting in a calculated velocity of 0.165281m/s for herself. The time to cover the distance of 45.3m is computed as 274 seconds, or approximately 4.6 minutes. However, the calculated answer was marked incorrect, indicating a potential arithmetic error that requires further investigation.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with basic physics equations: p=m*v, m1*v1=m2*v2, v=d/t
  • Knowledge of unit conversions (seconds to minutes)
  • Ability to perform arithmetic calculations accurately
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  • Review the conservation of momentum in isolated systems
  • Practice solving problems involving momentum and velocity
  • Learn about the effects of microgravity on motion
  • Explore common pitfalls in physics calculations and how to avoid them
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This discussion is beneficial for physics students, educators, and anyone interested in understanding momentum in space scenarios, particularly in relation to astronautics and motion dynamics.

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Momentum in Space --- How long will it take..?

Homework Statement



A 66kg astronaut becomes separated from the shuttle while on a space walk. She finds herself 45.3m away from the shuttle and moving with zero speed relative to the shuttle. She has a .912kg camera in her hand and decides to get back to the shuttle by throwing the camera at a speed of 12m/s in the opposite direction. How long will it take her to reach the shuttle? Answer in mins.

Homework Equations


p=m*v
m1*v1=m2*v2
v=d/t


The Attempt at a Solution


Since it is in space, I know that the momentum of the camera will equal that of the astronaut. So MassofCamera * VelocityOfCamera = MassOfAstronaut * VelocityOfAstronaut.
.912kg*12m/s=66kg*v2
v2= .165281m/s
Velocity is distance divided by time, so time = distance/velocity.
45.3m/.165281m/s = 274s = 4.6min. According to the quest homework system, this answer is wrong. Please help!
 
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Try checking your arithmetic - everything else looks fine
 

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