Electromagnetic Waves and Induction

[jlmessick88]

Homework Statement

The 2.0-cm-diameter solenoid in the figure passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.20 T.
What is the magnetic flux through the loop when it is perpendicular to the solenoid?
Φ1 = Wb

What is the magnetic flux through the loop when it is tilted at a 60 angle?
Φ2 = Wb

http://i63.photobucket.com/albums/h148/jlmessick88/jfk_Figure_25_P08.jpg

Homework Equations

Φ = AB cos()

The Attempt at a Solution

? No idea :(

Thanks

 

[cepheid]

You have the equation for calculating Φ. You have B. You have A. You have θ. What seems to be the trouble?

 

[jlmessick88]

getting confused with what i should be doing with the solenoid and the loop...wouldn't one effect the other or am i supposed to be using both diameters

 

[cepheid]

The question asks what the magnetic flux through the loop is. The loop does not have a magnetic field, so how could it affect the solenoid?

 

[jlmessick88]

oh! ok that makes sense...
but for when it's tilted 60 degrees... it would be .01^2 * pi = 3.14*10^-4 *.2T = 6.28*10^-5 * cos(60) = 3.14 * 10^-5...but that's not the correct answer...i don't understand why...

 

[cepheid]

The question asks what the magnetic flux through the loop is. The loop does not have a magnetic field, so how could it affect the solenoid?

EDIT:

The question asks what the magnetic flux through the loop is.

 

[jlmessick88]

What is the magnetic flux through the loop when it is perpendicular to the solenoid?
Express your answer using two significant figures.
=6.3×10−5
Correct
.01^2 * pi = 3.14*10^-4
3.14*10^-4 *.2 = 6.28*10^-5
6.28*10^-5 * cos(0) = 6.28*10^-5

so for the second part wouldn't i just use cos(60)??

 

[ideasrule]

What is the magnetic flux through the loop when it is perpendicular to the solenoid?
Express your answer using two significant figures.
=6.3×10−5
Correct
.01^2 * pi = 3.14*10^-4
3.14*10^-4 *.2 = 6.28*10^-5
6.28*10^-5 * cos(0) = 6.28*10^-5

so for the second part wouldn't i just use cos(60)??

Yes, you just use flux=BAcos(60). I don't know why you're doing:

.01^2 * pi = 3.14*10^-4
3.14*10^-4 *.2 = 6.28*10^-5
6.28*10^-5 * cos(0) = 6.28*10^-5

 

[jlmessick88]

but when i used BAcos(60), i get 3.14*10^-5, that's wrong...why??

 

[queenofbabes]

Not really seeing why the answer is wrong. What does your book say?

 

[jlmessick88]

i don't know what the answer is...it's just saying it's wrong...

 

[beccaboo2407]

Its the same answer for both.. even though I'm sure this is too late now