Electromagnetism: Turning effect of coil

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SUMMARY

The discussion focuses on the turning effect of a current-carrying coil positioned between the poles of a magnet. It is established that increasing the area of the coil enhances the turning effect, specifically through the lengths AB and CD. The inquiry revolves around whether increasing the length BC also contributes to the turning effect. The relevant formula for calculating the force on the conductor is F = BIl sin(α), where B represents magnetic induction, I is the current, l is the length of the conductor, and α is the angle between the conductor and the magnetic field.

PREREQUISITES
  • Understanding of electromagnetism principles
  • Familiarity with the formula F = BIl sin(α)
  • Knowledge of magnetic fields and forces on conductors
  • Basic concepts of current and coil configurations
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  • Research the impact of coil area on torque in electromagnetic systems
  • Explore the relationship between current, magnetic fields, and force on conductors
  • Study the effects of varying angles in magnetic field interactions
  • Investigate practical applications of electromagnetism in motors and generators
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Students studying physics, educators teaching electromagnetism, and engineers working with electromagnetic devices will benefit from this discussion.

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Homework Statement


This is a question about turning effect on a current-carrying coil lying between the poles of a magnet.
Please refer to the following link:
http://img11.picsplace.to/img.php?file=img10/22/N1_000.gif
On the textbook, it is stated the turning effect on the coil can be increased by increasing the area of the coil (inside the magetic field).
I understand the force would increase if AB and CD increases.
But I'm not sure whether the turning effect will increase when BC increases. :rolleyes:
Can anyone tell me?

Thank in advance.

Homework Equations





The Attempt at a Solution


 
Last edited by a moderator:
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The force acting on a current-carrying conductor could be calculated with the following formula:

F = BIl\sin\alpha

where B is magnetic induction, I is current, l is length of the conductor and <alpha> is the angle between the conductor and the magnetic field (the vector B). The angle between the conductor BC and the magnetic field is 0<pi> - the answer is thus apparent.
 
Last edited:

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