Careful here. N is the lower level and n is the upper level, not necessarily initial and final.David112234 said:1/L = R ( 1/N^2 - 1/n^2)
where N is initial and n final
alright,DrClaude said:Careful here. N is the lower level and n is the upper level, not necessarily initial and final.
Put the units in your equation, you will see where it went wrong.
Almost. I think it is simpler to make calculation using powers of 10 (less chance of an error):David112234 said:so it will be .0000004102m*10967760m^-1 = .449897515 m/m
You can't do that,David112234 said:Now I add 36 and take the sqrt
DrClaude said:Almost. I think it is simpler to make calculation using powers of 10 (less chance of an error):
410.2×10-9 m × 1.096779×107 m-1 = ?You can't do that,
$$
\frac{1}{a} + \frac{1}{b} \neq \frac{1}{a+b}
$$
You need to add 1/36 to 1 over the number you will get for λ×R.
That makes use of the properties of the logarithmDavid112234 said:I thought since all the terms were under 1 that I could just solve the denominators, like this property
X(2x+5) = x14
2x+5= 14
I used the Latex capabilities of PF. See https://www.physicsforums.com/help/latexhelp/ for more info.David112234 said:also, how do you display fractions on this forum like you did?
DrClaude said:That makes use of the properties of the logarithm
$$
\begin{align*}
x^a &= x^b \\
\log(x^a) &= \log(x^b) \\
a \log(x) &= b \log(x) \\
a &= b
\end{align*}
$$
It doesn't work for ##a^{-1} + b^{-1}##.I used the Latex capabilities of PF. See https://www.physicsforums.com/help/latexhelp/ for more info.
Indeed. I get a nice value. Could you show your calculation?David112234 said:I did it all out and the value I got it .66666, which still does not seem right
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