How Does 1,3-Butadiene Absorb UV Light in Terms of Particle-in-a-Box Theory?

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Discussion Overview

The discussion centers around the absorption of UV light by 1,3-butadiene, specifically through the lens of Particle-in-a-Box theory. Participants explore the modeling of pi electrons in conjugated systems and the calculations related to energy levels and photon absorption.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant outlines the problem involving the ground state energy of pi electrons in 1,3-butadiene, proposing that the energy of the highest energy electron can be expressed as a function of the box length (L) and the number of double bonds (N).
  • Another participant suggests that the energy levels can be calculated using the Schrödinger Equation, specifically noting the formula En = n²h²/(8mL²) for the energy levels of the electrons.
  • There is a mention of the need to determine the lowest energy light that the molecule can absorb, again as a function of L and N.
  • One participant expresses uncertainty about how to progress with the problem, indicating a lack of confidence in quantum mechanics.
  • Another participant reassures that the necessary information has been correctly listed and encourages further exploration of the problem.

Areas of Agreement / Disagreement

Participants generally express uncertainty and seek clarification on the problem, indicating that there is no consensus on how to proceed with the calculations or the application of the theory.

Contextual Notes

There are unresolved aspects regarding the application of the Particle-in-a-Box model to this specific problem, including the dependence on the definitions of L and N, and the implications of using the Schrödinger Equation.

Who May Find This Useful

Students or individuals interested in quantum mechanics, spectroscopy of conjugated molecules, or those working on related homework problems in physical chemistry or molecular physics.

terp.asessed
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Homework Statement


The UV/visible spectroscopy of linear conjugated molecules, particularly 1,3-butadiene in this problem, can often be modeled with the Particle-in-a-box of the electrons. Assume that we are interested in the pi electrons ONLY. A molecule with N double bonds = 2N pi electrons.

(1) To obtain the ground state, put 2N electrons in the LOWEST possible energy levels. Assume the box is of length L, what is the energy of the highest energy electron, as function of L and N?

(2) When 1,3-butadiene absorbs photon energy (hv), it uses the energy to promote 1 electron to a higher level. What is the lowest energy light the molecule can absorb, again, as a function of L and N?

Homework Equations


C-C bond length = 1.54 Angstrom
C=C length = 1.35 Angstrom
The angle between the bonds = 120 degree

L(in Angstrom) = (2.50)N - 1.32

The Attempt at a Solution


For butadiene, it has 2 double bonds...so N = 2 and 2(2) = 4 pi electrons, where 2 pi electrons compose energy level n=1 and second couple at n=2, with the possibility of one electron jumping to n=3 level with energy...

L = 2.50(2) - 1.32 = 3.68 Angstrom

...Could someone hint me as how to progress from here? I am stuck. Also, I know from the Schrödinger Equation that En = n2h2/(8mL2), from H wavefunction(x) = E wavefunction (x), where V(x) = 0 b/c of confinement inside a box...so, I wonder if I should use this equation too?
 
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terp.asessed said:
I wonder if I should use this equation too?

That would be my approach - it is just a matter of finding appropriate values of n (you already did part of the job earlier).

Disclaimer: QM is not something I feel confident about (but this particular problem looks rather straghtforward).
 
Okay...but, I am stuck as what the problem requests...especially as a function of N and L...Still, thank you.
 
Not sure what your problem is - looks to me like you have correctly listed all the necessary information in your attempts at solving the problem.
 

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