Electron beam energy to acceleration potential relation

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SUMMARY

The relationship between electron beam energy and accelerating potential is directly defined by the Electron Volt (eV), which quantifies the energy gained by an electron when accelerated through a potential difference of 1 Volt. In this discussion, it is established that a 6 kV supply will produce a 6 keV beam. Additionally, energy losses due to synchrotron radiation are acknowledged as dependent on the curvature of the beam path, particularly when bending the beam in a magnetic field. Understanding these principles is crucial for accurately calculating electron beam energy in practical applications.

PREREQUISITES
  • Understanding of Electron Volt (eV) and its significance in electron acceleration
  • Knowledge of accelerating potential and its role in electron beam generation
  • Familiarity with synchrotron radiation and its impact on energy loss
  • Basic principles of magnetic fields and their effect on electron beam paths
NEXT STEPS
  • Research the principles of synchrotron radiation and its calculations in electron beams
  • Study the effects of magnetic fields on electron beam trajectories
  • Explore the design and specifications of electron guns for optimal beam generation
  • Learn about energy loss mechanisms in particle accelerators and their implications
USEFUL FOR

Physicists, electrical engineers, and researchers involved in particle acceleration, synchrotron radiation studies, and electron beam technology will benefit from this discussion.

eigenmax
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Hi,
How can I relate the beam energy of an electron beam produced by an electron gun to the accelerating potential? I realize that accelerating potential, initial energy (before acceleation), and losses by synchrotron radiation, etc, will play a part.
I searched online and can't find much.
Thanks
 
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eigenmax said:
I searched online and can't find much
That's amazing. The Electron Volt is discussed in so many places and it is the energy that an electron gains when accelerated across a Potential Difference of 1V. Everything else hangs on that.
Energy loss by synchrotron radiation depends on the curvature of the path and is a different phenomenon. Try this link for a bit of insight.
 
Oh, about the synchrotron radiation, I was planning on bending the beam path in a magnetic field. Sorry, I must have been searching incorrectly. So my 6 kV supply should give a 6 kEv beam. Thanks, you've clarified a lot.
 
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