Electron moving between 2 charged plates

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The discussion centers on calculating the acceleration and final velocity of an electron moving between two charged parallel plates with a specified electric field. The initial attempt at finding acceleration used the formula A = (E*Q)/M, yielding an acceleration of -2.11 x 10^13 m/s² in the negative j direction. For the final velocity after a displacement of 1.4 cm, the calculations also resulted in -2.46 x 10^6 m/s in the j direction. Ultimately, the user discovered that their calculations were correct, but the system was not accepting the input format they used. This highlights the importance of adhering to specific input formats in online systems for accurate results.
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Homework Statement


at some instant the velocity components of an electron moving between two charged parallel plates are vx = 1.20 105 m/s and vy = 3.70 103 m/s. Suppose that the electric field between the plates is given by Evec = (120 N/C) jhat.

(a) What is the electron's acceleration in the field?
-2.11*E13 m/s2 jhat Incorrect

(b) What is the electron's velocity when its x coordinate has changed by 1.4 cm?
1.20*E5 m/s ihat + -2.46*E6 m/s jhat Incorrect


Homework Equations


F=ma
F=E*Q
V*T=D
V_0+A*T=V_1

The Attempt at a Solution


Rearranging the above equations i get A=(E*Q)/M

so A=(120*1.6*10^-19)/(9.1*10^-31)=2.11*10^13 jhat in the negative direction

Because acceleration is in the J direction there is no Iforce, so I is constant. so for D=t*V or t=d/v t=.014m/1.2*10^5=1.17*10^-7

then V_F=V_I+A*T so V_F=3.7*10^3+-2.11*10^13*1.17^10^-7=-2.46*10^6

Yet all of my answers are incorrect, what am i doing wrong?
 
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Never mind, my answer was correct but the system wasn't accepting the format i was inputting it as(which is ironically the format they fed the information to me in)
 
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