Electron spin in magnetic field

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SUMMARY

The discussion focuses on calculating the probability of finding an electron with spin down in a magnetic field represented by \(\vec B = (B \sin \theta, 0, B \cos \theta)\). The user attempts to derive the time evolution operator \(U(t)\) using the Hamiltonian \(\mathcal{H}\) and applies it to the initial state of the electron. However, the user encounters an error in their calculations, particularly in the treatment of the Pauli matrices, specifically \(\sigma_z\), and the properties of matrix exponentiation. The correct approach involves recognizing that the exponential of a matrix does not equal the matrix of the exponentials of its elements unless the matrix is diagonal.

PREREQUISITES
  • Quantum mechanics fundamentals, particularly spin states
  • Understanding of Hamiltonians and time evolution operators
  • Familiarity with Pauli matrices, especially \(\sigma_z\)
  • Matrix exponentiation techniques in quantum mechanics
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  • Study the derivation of the time evolution operator \(U(t)\) in quantum mechanics
  • Learn about the properties of Pauli matrices and their applications in spin systems
  • Explore the concept of matrix exponentiation and its implications in quantum mechanics
  • Investigate the role of magnetic fields in quantum systems and their effects on spin states
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Students and professionals in quantum mechanics, particularly those studying spin systems and magnetic interactions, as well as researchers working on quantum computing and related fields.

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Homework Statement


An electron is an eigenstate of sz at time t = 0 (spin up). It is in a magnetic field \vec B = (B \sin \theta, 0,B\cos\theta). Find the probability of finding the electron with spin down at time t.


Homework Equations


<br /> U(t) = \exp \left( -i \mathcal{H} t/\hbar\right)\\\\<br /> <br /> P(t) = \left| \left \langle \downarrow | \chi(t) \right \rangle \right|<br />


The Attempt at a Solution


<br /> \begin{align*}<br /> U(t) &amp;= \exp \left( -i \mathcal{H} t/\hbar\right)\\<br /> &amp;= \exp \left( -i \frac{et}{mc\hbar} \vec S \cdot \vec B\right)\\<br /> &amp;= \exp \left( -i \frac{\omega_0 t}{2} \left(\sigma_x \sin \theta + \sigma_z \cos \theta\right)\right)\\<br /> &amp;= \exp \left(-i \frac{\omega_0 t}{2} \left[ \begin{array}{cc}\cos \theta &amp; \sin \theta \\ <br /> \sin \theta &amp; \cos \theta \end{array}\right]\right)\\<br /> &amp;= \left( \begin{array}{cc}<br /> \exp (- i \frac{\omega_0 t}{2} \cos \theta) &amp; \exp (- i \frac{\omega_0 t}{2} \sin \theta)\\<br /> \exp (- i \frac{\omega_0 t}{2} \sin \theta) &amp; \exp ( i \frac{\omega_0 t}{2} \cos \theta)<br /> \end{array}\right)<br /> \end{align*}

Then at time t,
<br /> \begin{align*}<br /> \chi(t) &amp;= U(t) \left| \chi(0) \right \rangle\\<br /> &amp;= \left( \begin{array}{cc}<br /> \exp (- i \frac{\omega_0 t}{2} \cos \theta) &amp; \exp (- i \frac{\omega_0 t}{2} \sin \theta)\\<br /> \exp (- i \frac{\omega_0 t}{2} \sin \theta) &amp; \exp ( i \frac{\omega_0 t}{2} \cos \theta)<br /> \end{array}\right)\left( \begin{array}{c}1\\0\end{array}\right)\\<br /> &amp;= \left( \begin{array}{cc}<br /> \exp (- i \frac{\omega_0 t}{2} \cos \theta)\\<br /> \exp (- i \frac{\omega_0 t}{2} \sin \theta)\end{array}\right)<br /> \end{align*}<br />

But this gives P(t) = \left| (\begin{array}{cc} 0 &amp; 1 \end{array})\left( \begin{array}{cc}<br /> \exp (- i \frac{\omega_0 t}{2} \cos \theta)\\<br /> \exp (- i \frac{\omega_0 t}{2} \sin \theta)\end{array}\right)\right|^2 = 1, which is obviously wrong.

I've looked over my math and don't see any obvious mistakes, so I'm not sure what I'm doing wrong.



The Attempt at a Solution

 
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First, you have used for sigma_z the identity matrix. It should be 1 and -1 on the diagonal.
Also, you seemed to assume that the exponential of a matrix is the matrix of the exponentials of the elements of the initial matrix. This is not true in general (works only for a diagonal matrix)
 

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