Electronegativity / predicting structure / ranking order

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Discussion Overview

The discussion revolves around the concept of electronegativity and its implications for predicting the structure and bonding character of various chemical compounds, specifically focusing on CaBr2, Na3N, and CH4. Participants explore the differences in electronegativity, classify the compounds as ionic or molecular, and rank the bonds based on their ionic character.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant calculates the electronegativity differences for CaBr2, Na3N, and CH4, suggesting that CaBr2 and Na3N are ionic due to their high ∆EN values, while CH4 is molecular with a polar covalent bond.
  • Another participant emphasizes that ionic compounds have ionic bonds, and clarifies that the C-H bond in CH4 is generally considered non-polar covalent due to the small electronegativity difference.
  • A later reply adjusts the classification of CH4 to indicate it has a non-polar covalent bond, while reaffirming the ionic nature of CaBr2 and Na3N.
  • Participants discuss the ranking of the compounds based on ionic character, with Na3N being the most ionic, followed by CaBr2, and CH4 being the least ionic.

Areas of Agreement / Disagreement

There is some agreement on the classification of CaBr2 and Na3N as ionic compounds. However, there is a disagreement regarding the characterization of the C-H bond in CH4, with differing views on whether it should be classified as polar or non-polar covalent. The discussion remains unresolved on this point.

Contextual Notes

Participants express uncertainty regarding the classification of bonds and the implications of electronegativity differences, indicating that definitions and interpretations may vary. The discussion does not resolve the nuances of bond polarity in CH4.

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Homework Statement



a) Calculate the differences in electronegativity between the elements in each of these compounds.
I)CaBr2
II) Na3N
III) CH4
b) Predict whether each of these compounds would be an ionic or a molecular compound and justify each prediction.
c) Rank the bonds in these compounds in order of decreasing ionic character. Where do we always find compounds containing metals, in this ranking order?

Homework Equations


none.

The Attempt at a Solution



a)
i) CaBr_2
∆EN=2.9-1.0
=1.9
ii) Na_3 N
∆EN=3.0-0.9
=2.1
iii) CH_4
∆EN=2.5-2.2
=0.3
b)
i) CaBr_2
∆EN>1.7 ∴The compound is ionic and has a non-polar covalent bond
ii) Na_3 N
∆EN>1.7 ∴The compound is ionic and has a non-polar covalent bond
iii) CH_4
1.7>∆EN>0 ∴The compound is molecular and has a polar covalent bond
c)
Rank 1: Na_3 N Most Ionic Character
Rank 2: CaBr_2 2nd most Ionic Character
Rank 3: CH_4 Least Ionic Character
We find metals in compounds that form Ionic bonds when non-metals meet metals Ions form leading to one atom completely taking the electrons from the other atom since one of the atoms want to take atoms to complete their octet. This usually occurs with halogens in group 17 since they desperately want to complete their valence shell since every atom wants to be like the noble gases.
 
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Ionic compounds have ionic bonds, not covalent bonds. The electonegativity difference between C and H is small enough that most would consider the C-H bond to be a non-polar covalent bond (as opposed to something like an O-H bond or N-H bond, which would be considered polar covalent).

In terms of electonegativity difference (from largest difference to smallest difference), you would have:
Ionic > polar covalent > non-polar covalent
 
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I made some adjustments according to your comments:

b)
i) CaBr_2
∆EN>1.7 ∴The compound has an ionic bond
ii) Na_3 N
∆EN>1.7 ∴The compound has an ionic bond
iii) CH_4
0.4>∆EN>0 ∴The compound is molecular and has a non polar covalent bond
c)
Rank 1: Na_3 N Most Ionic Character
Rank 2: CaBr_2 2nd most Ionic Character
Rank 3: CH_4 Least Ionic Character ( non polar covalent bond)

What do you think? did I address the issues, sorry I'm still learning I'm very new to chemistry.
 
Looks good.
 
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