Electronic Devices byfloyd Problem

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The discussion centers on calculating the filter capacitor value "C" for a full wave rectifier circuit with a known output voltage of 18V. The user has identified the necessary parameters but lacks the Vr(Peak to Peak) value. The correct approach involves using the ripple factor to determine Vr(Peak to Peak) with the formula Vr(Peak to Peak) = Vp(Rectified) * Ripple Factor. Once this value is obtained, it can be substituted into the equation Vr(Peak to Peak) = (1/f * R(L) * C) * Vp(Rectified) to solve for C.

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extreme2000
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Dear users
In question i have to find the filter capacitor "C" value i have ripple factor given circut
is full wave rectifier circut R(L) is given V(out) of the rectifier is 18V I have calculated the V(peak)(rectified voltage) but in the following formula
Vr(Peak to Peak) =(1/f*R(L)C)*Vp(Rectified)
frequency is also known
I have done what
calculated the V(Rectified Volatge)all other things are also known but two things are missing in above equation the Vr(Peak to Peak) if this is know by any means I can then calculate the value of Filter capacitor C any help? I have to submit the assingment tomorrow
Thanks
 
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The formula you have is correct and you have all the necessary parameters except for Vr(Peak to Peak). You need to determine this value in order to find the value of C. To do this, you can look up the ripple factor of your full wave rectifier circuit and use that to calculate Vr(Peak to Peak) using the following formula: Vr(Peak to Peak) = Vp(Rectified)* Ripple Factor. Once you have this value, you can plug it into the original equation to solve for C.
 

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