Electronics (Diodes + capacitors) questions

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Homework Help Overview

The discussion revolves around understanding concepts related to electronics, specifically focusing on diodes and capacitors in the context of a year 12 physics curriculum. Participants express confusion over the material presented in their textbook, particularly regarding the derivation of answers and the interpretation of graphs.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between charge, voltage, and current in capacitors, referencing specific equations and expressing confusion about the graph and symbols used in their textbook.
  • Some participants suggest reviewing specific sections of the textbook that cover the differential equation relating current and voltage in capacitors.
  • Others question how different values are derived from the equations and the significance of the graph presented.

Discussion Status

The discussion is ongoing, with participants sharing their attempts to apply formulas and seeking clarification on various aspects of the problem. There is no explicit consensus, but some guidance has been provided regarding the interpretation of symbols and the equations involved.

Contextual Notes

Participants note that the textbook lacks detailed explanations for the answers provided, leading to confusion. There is an emphasis on understanding the underlying principles rather than just the final answers.

Nauraushaun
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I've been working through our physics book for year 12 Physics, and only just now when we've hit electronics has it really confused me. I'd like to be able to understand it before our current 2 week school break ends.
Perhaps the biggest flaw of the book is that it doesn't say how it got answers, it only says what the answer is.
So if I can get help with this, I might post a few more I'm having trouble with. Hopefully I'll be getting the hang of it very soon. When the teacher explains it to me in class I can get it, but it seems every question I hit has some new element that the book has never explained.

Homework Statement


http://img209.imageshack.us/img209/9649/q11fg1.jpg
http://img209.imageshack.us/img209/308/q12pj6.jpg

Homework Equations


-


The Attempt at a Solution


I looked at the answer in the book, it's something very similar to this:
http://img206.imageshack.us/img206/2451/q1atp0.jpg
I tried to find the numbers they got, but the only thing I could thing of was C=Q/V, and I don't have a C or a Q to put in there.
And the graph confused me.
I'm not sure how they got the numbers they got, why the graph does what it does, or what that little U symbol means.
Could someone please explain how and why for me? Thank you very much.
 
Last edited by a moderator:
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Nauraushaun said:
I've been working through our physics book for year 12 Physics, and only just now when we've hit electronics has it really confused me. I'd like to be able to understand it before our current 2 week school break ends.
Perhaps the biggest flaw of the book is that it doesn't say how it got answers, it only says what the answer is.
So if I can get help with this, I might post a few more I'm having trouble with. Hopefully I'll be getting the hang of it very soon. When the teacher explains it to me in class I can get it, but it seems every question I hit has some new element that the book has never explained.

Homework Statement


http://img209.imageshack.us/img209/9649/q11fg1.jpg
http://img209.imageshack.us/img209/308/q12pj6.jpg

Homework Equations


-


The Attempt at a Solution


I looked at the answer in the book, it's something very similar to this:
http://img206.imageshack.us/img206/2451/q1atp0.jpg
I tried to find the numbers they got, but the only thing I could thing of was C=Q/V, and I don't have a C or a Q to put in there.
And the graph confused me.
I'm not sure how they got the numbers they got, why the graph does what it does, or what that little U symbol means.
Could someone please explain how and why for me? Thank you very much.

[tex]C = \frac{Q}{V}[/tex]
[tex]I = C\frac{dV}{dt}[/tex]
I = slope * C
 
Last edited by a moderator:
The current and voltage in a capacitor are related by a differential equation: [itex]i(t)=C\frac{dv(t)}{dt}[/itex]. Try to find this section in your book and study it.

The [itex]\mu[/itex] sign is a prefix meaning "one-millionth."
 
So if I use either of those formulas...
I = C*(dV/dt)
I = 10*(5/1)
I = 50
I get 50, mA I presume. But how did they get -100 as well, and the graph they've got?
 

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