I Electrons from Internal Conversion

Zuzana
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Hi,
I would like to ask, why K-shell electrons coming from the internal conversion are much more frequent than L or M-shell electrons (see Fig). K-shell electrons are more tightly bound than L-shell, I would say that it is easier for gamma particle to kick off less tightly electron, no?
1650994503436.png

Thank you in advance for the reply.
 
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The probability of an electron being found within the nucleus decreases as the shell increases. It is more probable for a K electron to be involved in the internal conversion process than an L or M electron.
 
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DrClaude said:
The probability of an electron being found within the nucleus decreases as the shell increases. It is more probable for a K electron to be involved in the internal conversion process than an L or M electron.
what do you mean by "within the nucleus"? electrons are at the atomic orbitals (shells outside the nucleus).
 
Zuzana said:
what do you mean by "within the nucleus"? electrons are at the atomic orbitals (shells outside the nucleus).
No, the wave function is extended. There is a non-zero probability of finding the electron at the nucleus.
1651071416430.png
 
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Aha, DrClaude beat me to it while I was Googling. Here's another set of examples:

http://hyperphysics.phy-astr.gsu.edu/hbase/hydwf.html

The probability of the electron having a small-enough value of ##r## to be inside the nucleus, is smaller for excited states (e.g. L-shell i.e. 2s, 2p) than for the ground state (K-shell i.e. 1s).
 
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Now, I understand. Thanks a lot for the reply.
 
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On the graphs at the link that I posted, the horizontal axis is given as multiples of ##a_0##, the Bohr radius (the radius of the K shell in the Bohr model).

Exercise: look up typical values for the radius of nuclei that undergo internal conversion, and compare to ##a_0##, so as to see what part of those graphs comes into play in internal conversion.
 
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