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Homework Statement
fig 1 : Area of each plate is S, separated by 2d, charge Q in the capacitors
fig 2 : uncharged conductors of area S, thickness d, inserted parallel between plates
What is the ratio of electrostatic energy in fig 2 to electrostatic energy in fig 1?
Homework Equations
Q = CV
C = Q/V = Q/Ed = ##\frac{Q \epsilon} {charge density * d}## = ##\frac { A\epsilon}{d} ##
energy stored in capacitor = ##\frac{1}{2} CV^2##
E = qV (in general)
E = qV (in general)
The Attempt at a Solution
I think the electrons will be like this
ratio = ##\frac{C_1 {V_1}^2 }{ C_2 {V_2} ^2}## = ##\frac{\frac { A\epsilon}{d} {V_1}^2 }{ \frac { A\epsilon}{d} {V_2} ^2}##
are the voltages the same between fig 1 and fig 2?
how to find the ratio?
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